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3 years ago

12

Can somebody give me an answer to this it would be really helpful thanks!

2 answers:

kvv77 [185]3 years ago

7 0

Answer:

.625 for decimal, and 62.5 percent.

Step-by-step explanation:

1/8 is 1.25 and that times 5 is .625. .625 * 100 = 62.5

Please give me brainliest

Drupady [299]3 years ago

5 0

Answer:

The decimal is 0.625

The percent is 62.5%

Step-by-step explanation:

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Darina [25.2K]

<span>tan θ is defined as the opposite/adjacent side to the angle in a triangle

in this case you have a triangle which forms from (0,0) to (5,0) and (5,15), with </span><span>θ at (0,0)

-> your x coordinate is the adjacent side, and y the opposite
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<span>tan θ=opposite/adjacent=y/x=15/5=3</span>

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3 years ago

Heyy pls help! worth 20 points, and please only help if you know the answer. also no links those r kinda annoying lol

iragen [17]

Step 1: Find the slope:

$m= \dfrac{y_2-y_1}{x_2-x_1}= \dfrac{-2-7}{4-(-2)} = \dfrac{-9}{6}= -\dfrac{3}{2}$

This gives you $y=-\dfrac{3}{2}x+b$ , but we need to find b.

To find b, substitute in one (x,y) pair and it doesn't matter which one. I'll go with (4,-2):

$\begin{aligned}-2&=-\dfrac{3}{2}(4)+b\\[0.5em]-2&=-6+b\\[0.5em]4&=b\end{aligned}$

Now take that b-value and plug in into the slope-intercept form:

$y=-\dfrac{3}{2}x+4$

It's always a good idea to toss in the other x-value from the other point, to make sure it checks out.

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m_a_m_a [10]

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Step-by-step explanation:

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2 years ago

Carla is selling chocolate bars for a fundraiser. Her goal is to sell 600 chocolate bars to win the top prize for selling them.

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3 years ago

What is lim x→-3 sqrt x^2-8

vitfil [10]

If the -8 is under the square root, then...

$\displaystyle L = \lim_{x\to -3} \sqrt{x^2-8}\\\\L = \sqrt{(-3)^2-8}\\\\L = \sqrt{9-8}\\\\L = \sqrt{1}\\\\L = 1\\\\$

OR

If the -8 is not under the square root, then...

$\displaystyle L = \lim_{x\to -3} \sqrt{x^2}-8\\\\L = \sqrt{(-3)^2}-8\\\\L = \sqrt{9}-8\\\\L = 3-8\\\\L = -5$

Either way, we replace x with -3 and simplify.

For more information, refer to the direct substitution rule for limits.

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1 year ago