Can somebody give me an answer to this it would be really helpful thanks!
2 answers:
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Given:
The conversions from meter to inches and inches to meter are shown in part A of model 2.
The conversions from liters to quarts and quarts to liters are shown in part B of model 2.
Required:
To find the relationship between the conversion factors used in Part A of Model 2.
To find the relationship in the the conversion factors used in Part B of Model 2.
Explanation:
We have given that 1 meter = 39.4 inches.
Thus, from the calculations shown in part A of model 2, we can conclude that the quantity from meters to inches is converted as:
Thus, 1.5 m =59 inches.
Also, the quantity from inches to meters is converted as:
Hence, 59 in = 1.5 m.
Next,
We have 1 L = 1.06 qt.
Thus, from the calculations shown in part B of model 2, we can conclude that the quantity from quarts to liters is converted as:
Thus, 186 quarts = 175 L.
Also, the quantity from liters to quarts is converted as:
Hence, 175 L = 186 qt.
Final Answer:
We conclude that:
While converting from meters to inches, we multiply the quantity 1.5 by the equality quantity given.
While converting from incehs to meters, we divide the quantity 59 by the equality quantity given.
Also, While converting from quarts to liters, we divide the quntity 186 by the equality quantity given.
While converting from liters to quarts, we multiply the quntity 175 by the equality quantity given.
Answer:
Interest earned = $32.835
Step-by-step explanation:
Given the following data;
Principal = $275
Number of times = 0.5
Interest rate = 2.9% = 0.029
Time = 4 years
To find the interest earned, we would use the compound interest formula;
Where;
A is the future value.
P is the principal or starting amount.
r is annual interest rate.
n is the number of times the interest is compounded in a year.
t is the number of years for the compound interest.
Substituting into the equation, we have;
A = $307.835
Interest earned = 307.835 - 275
Interest earned = $32.835
Answer:
<u>Volume = 1.535</u>
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Step-by-step explanation:
The region R is bounded by the equations:
y = √sin⁻¹x
y = √(π/2)
y = √(π/3)
x = 0
R is revolved around the x-axis so we will need f(y) for finding out the volume. We need to make x the subject of the equation and then replace it with f(y).
f(x) = √sin⁻¹x
y = √sin⁻¹x
Squaring both sides we get:
y² = sin⁻¹x
x = sin (y²)
f(y) = sin (y²)
Using the Shell Method to find the volume of the solid when R is revolved around the x-axis:
The limits a and b are the equations y = √(π/2) and y = √(π/3) which bound the region R. So, a = √(π/2) and b = √(π/3).
V = 2π sin (y²) dy
Integrating sin (y²) dy, we get:
-cos(y²)/2y
So,
V = 2π [-cos(y²)/2y] with limits √(π/2) and √(π/3)
V = 2π [(-cos(√(π/2) ²)/2*√(π/2)] - [(-cos(√(π/3) ²)/2*√(π/3)]
V = 2π [(-cos(π/2)/ 2√(π/2)) - ((-cos(π/3)/ 2√(π/3))]
V = 2π [ 0 - (-0.5/2.0466)]
V = 2π (0.2443)
V = 1.53499 ≅ 1.535