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Rzqust [24]
3 years ago
10

(WILL GIVE BRAINLIEST)

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

m<I=57

m<J=57

m<K=66

Step-by-step explanation:

All the angles in a triangle add up to 180 degrees.

m<I= 3x+18

m<K= 5x+1

m<I is congruent to m<J.

We can plug the information we already know into the equation.

3x+18+3x+18+5x+1=180

11x+37=180

Subtract 37 from both sides.

11x=143

x=13

Now, we can find out what the angles are.

m<I= 3x+18

m<I=3(13)+18

m<I=39+18

m<I=57

We know that m<I=m<J, so they are both equal to 57 degrees.

m<J=57

Now for m<K:

m<K=5x+1

m<K=5(13)+1

m<K=65+1

m<K=66

We know this is correct because 57+57+66=180.

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You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of t
natka813 [3]

Hello AljakeVillena!

\huge \boxed{\mathfrak{Question} \downarrow}

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

Given,

  • mass of crate = 50 kg
  • Force you pull it with = 450 N
  • Frictional force = 250 N
  • Acceleration = ?

__________________

Let's first find the total force/net force acting on the crate. The total force will be :-

  • 450 N - 250 N = <u>2</u><u>0</u><u>0</u><u> </u><u>N.</u>

We subtracted the forces because both the forces act on opposite directions.

__________________

Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..

  • Acceleration = Force/mass
  • a = F/m
  • a = 200/50
  • <u>a = 4 m/s²</u>

__________________

So, the acceleration of the crate is <u>4</u><u> </u><u>m/</u><u>s²</u><u>.</u>

__________________

Hope it'll help you!

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6 0
3 years ago
What does this expression mean? 4 to the 3rd power
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The fourth option is the answer
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Solve using Y=Mx+b <br><br> M=-5 and (-3,-2)
3241004551 [841]

Given:

M=-5 and (-3,-2).

To find:

The equation in the form y=mx+b.

Solution:

The slope intercept form of a line is

y=mx+b          ...(i)

where, m is slope and b is y-intercept.

We have m=-5. Putting m=-5 in (i), we get

y=-5x+b          ...(ii)

We have a point (-3,-2). Putting x=-3 and y=-2 in (ii), we get

-2=-5(-3)+b

-2=15+b

-2-15=b

-17=b

So, the value of b is -17.

Putting b=-17 in (ii), we get

y=-5x+(-17)

y=-5x-17

Therefore, the required equation is y=-5x-17.

8 0
3 years ago
Which equation represents an exponential function that passes through the point (2, 80)?
s2008m [1.1K]

Answer:

D) f(x) = 5(4)ˣ

Explanation:

(x, y) = (2, 80)

Check by inserting x = 2

A) y = 4(x)⁵ = 4(2)⁵ = 128

B) y = 5(x)⁴ = 5(2)⁴ = 80  - passes

C) y = 4(5)ˣ = 4(5)² = 100

D) y = 5(4)ˣ = 5(4)² = 80 - passes

An exponential equation is in a(b)ˣ format, so only f(x) = 5(4)ˣ is an exponential equation which passes the point (2, 80)

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Answer:

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Step-by-step explanation:

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