Hello AljakeVillena!

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

Given,
- mass of crate = 50 kg
- Force you pull it with = 450 N
- Frictional force = 250 N
- Acceleration = ?
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Let's first find the total force/net force acting on the crate. The total force will be :-
- 450 N - 250 N = <u>2</u><u>0</u><u>0</u><u> </u><u>N.</u>
We subtracted the forces because both the forces act on opposite directions.
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Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..
- Acceleration = Force/mass
- a = F/m
- a = 200/50
- <u>a = 4 m/s²</u>
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So, the acceleration of the crate is <u>4</u><u> </u><u>m/</u><u>s²</u><u>.</u>
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Hope it'll help you!
ℓu¢αzz ッ
The fourth option is the answer
Given:
M=-5 and (-3,-2).
To find:
The equation in the form
.
Solution:
The slope intercept form of a line is
...(i)
where, m is slope and b is y-intercept.
We have m=-5. Putting m=-5 in (i), we get
...(ii)
We have a point (-3,-2). Putting x=-3 and y=-2 in (ii), we get




So, the value of b is -17.
Putting b=-17 in (ii), we get


Therefore, the required equation is
.
Answer:
D) f(x) = 5(4)ˣ
Explanation:
(x, y) = (2, 80)
Check by inserting x = 2
A) y = 4(x)⁵ = 4(2)⁵ = 128
B) y = 5(x)⁴ = 5(2)⁴ = 80 - passes
C) y = 4(5)ˣ = 4(5)² = 100
D) y = 5(4)ˣ = 5(4)² = 80 - passes
An exponential equation is in a(b)ˣ format, so only f(x) = 5(4)ˣ is an exponential equation which passes the point (2, 80)
Answer:
Its A <3
Step-by-step explanation: