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Novosadov [1.4K]
3 years ago
10

Explain how to solve angle relationship problems

Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0

Answer:


Step-by-step explanation: Identify the angle relationships, set up the equation that will yield the unknown value, solve the equation for the unknown value, substitute the answer to determine the measurement of the angles then, check and verify your answer by measuring the angle with a protractor.


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Tim predicts he will get 98 points on the next exam. If Tim actually earned 62 points, what was Tim's percent error? Round your
cupoosta [38]
% change= (new # - original #) ÷ original # x 100

original #= 98
new #= 62

% change= (62-98)/98 x 100
= -36/98 x 100
= -0.36734 x 100
= -36.73%

Rounded to nearest 10th of %= -36.7%

CHECK:
= 98 - (98 * 36.73%)
= 98 - (98 * 0.3673)
= 98 - 36
= 62 new #

ANSWER:
Her percent error was 36.7% (rounded to the nearest tenth of a percent). The negative indicates a decrease.

Hope this helps! :)
5 0
3 years ago
Read 2 more answers
Find the scale factor for the dilation. please show your work.<br><br> X (3. 6) X' (2, 4)
Anastasy [175]

Answer:

Step-by-step explanation:

4/6=2/3

2/3=2/3

scale factor=2/3

6 0
3 years ago
From the information given determine the quadrant in which the terminal point (determined by an angle with a measure of a) lies.
Otrada [13]

Answer:

If sin(θ)<0 and cos(θ)<0), then (x,y) lies in quadrant III.

If sin(θ)>0 and cos(θ)<0), then (x,y) lies in quadrant II.

If sin(θ)>0 and cos(θ)>0), then (x,y) lies in quadrant I.

If sin(θ)<0 and cos(θ)>0), then (x,y) lies in quadrant IV.

Step-by-step explanation:

Sine and cosine values, relation with quadrant:

Quadrant 1: Sine > 0, cosine > 0.

Quadrant 2: Sine > 0, cosine < 0.

Quadrant 3: Sine < 0, cosine < 0.

Quadrant 4: Sine < 0, cosine > 0.

If sin(θ)<0 and cos(θ)<0), then (x,y) lies in quadrant

Both negative, so III.

If sin(θ)>0 and cos(θ)<0), then (x,y) lies in quadrant

Sine positive, cosine negative, so II.

If sin(θ)>0 and cos(θ)>0), then (x,y) lies in quadrant

Both positive, so I.

If sin(θ)<0 and cos(θ)>0), then (x,y) lies in quadrant

Sine negative, cosine positive, so IV.

6 0
3 years ago
In the xy-plane, line l has a y-intercept of -13 and is perpendicular to the line with the equation y=-2/3x. If the point (10, b
AlekseyPX

Answer:

The value of b is 2.

Step-by-step explanation:

The standard form of the equation of the line is of the form:

y = m\cdot x + k

Where:

x, y - Independent and dependent variable, dimensionless.

m - Slope, dimensionless.

k - y-intercept, dimensionless.

Given that line l is perpendicular to y = -\frac{2}{3}\cdot y, the slope is equal to:

m = -\frac{1}{m_{\perp}}

Where m_{\perp} is the slope of the perpendicular line, dimensionless.

If m_{\perp} = -\frac{2}{3}, then:

m = -\frac{1}{\left(-\frac{2}{3}\right) }

m = \frac{3}{2}

If x = 0 and y = -13, the y-intercept of the line l is:

-13 = \frac{3}{2}\cdot (0) +k

k = -13

The equation of the line l is y = \frac{3}{2}\cdot x -13. Given that y = b and x = 10, the value of b is:

b = \frac{3}{2}\cdot (10)-13

b = 15-13

b = 2

The value of b is 2.

5 0
3 years ago
Ten more than-one third of a number is sixteen. Which of the following represents the number?
mart [117]
I want to say b. 18
Hope I helped
5 0
3 years ago
Read 2 more answers
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