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3 years ago

Jubal wrote the four equations below. He examined them, without solving them, to determine which equation has no solution.

Mathematics

2 answers:

madreJ [45]3 years ago

5 0

Answer:

3x+2=3x-2

Step-by-step explanation:

The second equation has no solution, because is not true

3x+2=3x-2 ------> is not true

therefore

The equation has no solutions

Ilya [14]3 years ago

4 0

Answer:

$3x+2=3x-2$

Step-by-step explanation:

When an equation has no solution there's no true value for x. What we have is a Contradiction, a false answer.

1)The first and the last equation has a true solution in the form:

$0x=0$

True

2)The third one has a solution:

$x=7$

True

3) The second one

$3x+2=3x-2\\0x=-4$

FALSE

A Contradiction. Then, this one has no solution.

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5/6 x 2 3/4 = 5/6 x (2x4+3)/4 = 5/6 x 11/4 = 55/24 = 2 7/24

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You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago

An ice cream cone is 5" deep and 2" in top diameter. One scoop of vanilla ice cream, 2" in diameter, is placed on the cone. If t

Ratling [72]

If the total volume of the ice cream exceeds the internal volume of the cone, then it will overflow.

Volume of icecream = 4/3 * pi * r^3 = 4/3*pi*(1)^3 = 4.189 cu. in.Volume of cone = 1/3 * pi * r^2 * h = 1/3*pi*(1)^2*5 = 5.236 cu. in.

Since Volume of cone > Volume of icecream, the cone will not overflow.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

5 0

3 years ago

An architect designed this scale model of a warehouse for a building contractor.

Annette [7]

tl;dr Answer is C

Here we will have to calculate 3 different areas separately.

When calculating the area of the triangle we will use the formula

A = (h*b)/2

A = Area

h = height

b = base

To find the height we do X - Z

23 - 15 = 8 ft

To find the base we do Y - W

19 - 13 = 6 ft

Using the formula above we can now solve for A

A = (8*6)/2

A = (48)/2

A = 24 sq ft

Now we solve the two rectangles using the formula

A = wl

w = width

l = length

We will calculate the area of the left most rectangle first.

We know the length of the rectangle because it's Y - W and we are given the width of the triangle.

w = 15 ft

l = 6 ft

A = 15*6

A = 90 sq ft

Second Rectangle has the width of X and length of W

w = 23 ft

l = 13 ft

A = 23 * 13

A = 299 sq ft

Now we add all the areas to give us the total area of the warehouse.

24 + 90 + 299 = 413 sq ft

Therefore, the answer is C

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3 years ago