Answer:
Step-by-step explanation:
Given that a parking lot has two entrances. Cars arrive at entrance I according to a Poisson distribution at an average of 3 per hour and at entrance II according to a Poisson distribution at an average of 2 per hour.
Assuming the number of cars arriving at the two parking lots are independent we have total number of cars arriving X is Poisson with parameter 3+2 = 5
X is Poisson with mean = 5
the probability that a total of 3 cars will arrive at the parking lot in a given hour
= P(X=3) = 0.1404
b) the probability that less than 3 cars will arrive at the parking lot in a given hour
= P(X<3)
= P(0)+P(1)+P(2)
= 0.1247
X=Marks sister's age
x+11= Marks age
x+11 +8 = 2x+8
x+19=2x +8
x+19-x=2x-x +8
19-8=x+8-8
11=x Marks sisters age in 8 years
11-8= 3 Marks sisters age now
x+11=22 Marks age in 8 years
22-8= 14 Marks age now
I've got the answer It's this
Answer:
Total Cost for Pretzels and juice is $9.
Step-by-step explanation:
Given:
Number of Bags of pretzels =3
Cost for each bag = $2.00
Total Cost of Pretzels is equal to product of Number of Bags of pretzels and Cost for each bag.
Framing in equation form we get;
Total Cost of Pretzels = 
Also Given:
Number of Bottle of Juice = 2
Price of each bottle = $1.5
Total Cost of Juice is equal to product of Number of Bottle of Juice and Price of each bottle.
Framing in equation form we get;
Total Cost of Juice = 
Total Cost of Pretzels and juice is equal to sum of Total Cost of Pretzels and Total Cost of Juice.
Total Cost of Pretzels and juice = Total Cost of Pretzels + Total Cost of Juice
Total Cost of Pretzels and juice = $6 + $3 =$9
Hence Total Cost for Pretzels and juice is $9.
Answer:

Step-by-step explanation:
I'd assume this is a dice? Please give more information.