Answer:
Las moléculas de los reactivos tienen que chocar entre sí. Estos choques deben de producirse con energía suficiente de forma que se puedan romper y formar enlaces químicos. En el choque debe haber una orientación adecuada para que los enlaces que se tienen que romper y formar estén a una distancia y posición viable.
The correct answer is A. Charging by friction
Explanation
When someone rubs a comb with their hair when they are combing it and the hair sticks to the comb occurs a phenomenon called electrization, in which a neutral body becomes charged or loses an electrical charge (electrons). One way that electrization occurs is through the rubbing of two neutral bodies which causes one to be positively charged and the other negatively causing them to attract each other by magnetism. Therefore, the correct answer is A. Charging by friction
C-12? (6 protons) C-13? (6 protons) C-14? (6 protons)
Answer:
355.5 g.
Explanation:
- The balanced equation for the mentioned reaction is:
<em>2Al + 6HCl → 2AlCl₃ + 3H₂,</em>
It is clear that 2.0 moles of Al react with 6.0 mole of HCl to produce 2.0 moles of AlCl₃ and 3.0 mole of H₂.
- Firstly, we need to calculate the no. of moles of (87.7 g) of Al:
no. of moles of Al = mass/atomic mass = (87.7 g)/(26.98 g/mol) = 3.251 mol.
<em><u>Using cross multiplication:</u></em>
2.0 mol of Al need to react → 6.0 mol of HCl, from stichiometry.
3.251 mol of Al need to react → ??? mol of HCl.
∴ the no. of moles of HCl needed to react with (87.7 g) 3.251 mol of Al = (3.251 mol)(6.0 mol)/(2.0 mol) = 9.752 mol.
- Now, we can get the mass of HCl needed to react with (87.7 g) 3.251 mol of Al:
<em>mass of HCl = (no. of moles)(molar mass) </em>= (9.752 mol)(36.46 g/mol) = <em>355.5 g.</em>
Answer:
4 sig figs
Explanation:
There are 4 because they are all # 1 or above.
0 has special rules on whether or not it is significant.
0 being between two other sig figs no matter how far apart makes it a sig fig.
example: 101 is 3 sig figs
0 that is at the end of a non decimal number are not significant.
example: 110 is 2 sig figs
0 that are after a decimal are significant as long as they after another sig fig.
example: 1.000 and .1000 are both 4 sig figs
extra examples:
110.01 is 5 sig figs
110.1 is 4 sig figs
.0001 is 1 sig figs
