The empirical formula of this compound is ![Fe_2O_3](https://tex.z-dn.net/?f=Fe_2O_3)
<h3>Empirical formula </h3>
To calculate the empirical formula of a compound, the value of moles of each element is needed.
As we have the information of the mass value, we will use the molar mass expression, which corresponds to:
![MM_O = 16g/mol\\MM_Fe = 55.8g/mol](https://tex.z-dn.net/?f=MM_O%20%3D%2016g%2Fmol%5C%5CMM_Fe%20%3D%2055.8g%2Fmol)
![MM = \frac{m}{mol}](https://tex.z-dn.net/?f=MM%20%3D%20%5Cfrac%7Bm%7D%7Bmol%7D)
![16 = \frac{4.8}{x}](https://tex.z-dn.net/?f=16%20%3D%20%5Cfrac%7B4.8%7D%7Bx%7D)
![x = 0.3mol](https://tex.z-dn.net/?f=x%20%3D%200.3mol)
![55.8=\frac{11.2}{x}\\x = 0.2](https://tex.z-dn.net/?f=55.8%3D%5Cfrac%7B11.2%7D%7Bx%7D%5C%5Cx%20%3D%200.2)
As the value of the empirical formula must be an integer, simply multiply the two values by a common factor:
![O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2](https://tex.z-dn.net/?f=O%20%3D%200.3%20%5Ctimes%2010%20%3D%203%5C%5CFe%20%3D%200.2%20%5Ctimes%2010%20%3D%202)
![Fe_2O_3](https://tex.z-dn.net/?f=Fe_2O_3)
So, the empirical formula of this compound is
.
Learn more about empirical formula: brainly.com/question/1247523
Fluorine has the highest. Fluorine's electronegativity is 4.0
Answer:
a. 50ml b.10ml c. 6.097ml d. 190.1 ml
Explanation:
According to Boyle's law
Volume is inversely proportional to pressure at constant temerature
Mathematically
P1V1=P2V2
P1=Initial pressure=0.8atm
V1=Initial volume=25ml
making V2 the subject
at 0.4atm P2=0.4 atm,
V2=25×0.8/0.4
=50ml
at 2 atm V2=25×0.8/2
=10 ml
1mmHg=0.00131579
2500mmHg=3.28 atm
At 3.28 atm,V2=25×0.8/3.28
=6.097 ml
at 80.0 torr
1 torr=0.00131579
80 torr=0.1052 atm
at 0.1048 atm V2=25×0.8/0.1048
=190.1 ml
Answer:
sorry please can you snap the diagram ...the question is not clear to my understanding