8. How many protons are in C-12? C-13? C-14?

Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1

givi [52]

According to Hasselbach-Henderson equation:

$pH=pK_{a}+log\frac{[A^{-}]}{[HA]}$

Here, $[A^{-}]$ is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is $CH_{3}COOK$ and acid is $CH_{3}COOH$ thus, Hasselbach-Henderson equation will be as follows:

$pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}$ ...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{2}{1}=5.06$

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{3}=4.28$

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{5}{1}=5.45$

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{1}=4.76$

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{10}=3.76$

Therefore, pH of solution is 3.76.

4 0

3 years ago

Calculate the mass of 1.00 mol of each of these substances

bogdanovich [222]

What are the substances?

7 0

4 years ago

Which of the following is equal to an impulse of 18 units?

dem82 [27]

The answer is force=6, time=3, so C is correct

8 0

3 years ago

Read 2 more answers

10g of an unknown compound are added to water to form a 7.89 molar solution. if 2 liters of solution are present, what is the mo

Citrus2011 [14]

10 / (7.89) (2)

molarity equation is M = Moles of solute / Liters of solution

7.89 = Moles of solute / 2

(7.89)(2). The question asks for the molar mass which is defined as g/mol. Dividing would give you the unknown compound.

MM = 10g / (7.89)(2)

6 0

4 years ago

Balance the equation and show the calculation of the number of moles and grams of CO2 formed from 11.9 grams of O2. Show your an

n200080 [17]

Answer:

0.2349 moles, 10.3356 g

Explanation:

The given reaction is :

$C_6H_{14}+O_2\rightarrow CO_2 + H_2O$