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Wewaii [24]
3 years ago
9

The staff members working in Radiology department in hospitals, wear shoes with special soles. Justify

Chemistry
1 answer:
ella [17]3 years ago
6 0

Answer:

Radiology departments in hospitals use x-rays, MRIs, CT scans, etc. on a daily basis, meaning they are heavily exposed to radiation without protective equipment, and said exposure can cause cancer down the line and shorten their life significantly. To prevent this from happening, they give the radiologist (and the patient) with equipment with lead (and other materials) which reflects or absorbs the radiation from these scans, including shoes with special soles. These shoes are most likely worn due to the radiation left in the scanning room floors after scans. Radiologists also go to a special room with heavy radiation protection where they can activate and monitor the scan.

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An experiment reveals that 125.0 grams of an unknown metal increases in temperature from 22.0 oC to 43.6 oC upon absorbing 640 j
nydimaria [60]

Answer:

                     Cp  =  0.237 J.g⁻¹.°C⁻¹

Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

3 0
3 years ago
PLEASE PLEASE HELP ME!! I WILL BRAINLIST YOU!! A 28.0 g sample of N2 is in a rigid 4.50 L container at 32 °C. Calculate the pres
chubhunter [2.5K]

Answer:

P=4184.36 torr

Explanation:

For this problem we can use the idea gas law,

PV=nRT

where P is pressure, V is volume, n is moles of substance, R is the constant, and T is temperature, We will need to manipulate it and a couple values so that we can get our answer in torr. To do this, let's rearrange the equation to solve for P.

P=\frac{nRT}{V}

Next, let's convert T (32) to kelvin. To do this, add 273 to the value.

32+273=305

Next, let's convert 28g of N2 to moles of N2. To do this, divide 28 by the molar mass of N2 (28.02)

\frac{28.0}{28.01} \\=.99 moles of N2

Next, we need to find out what value of R we need to use. Because you want your answer in torr, we will need to use the value of

R=62.36\frac{torr}{mol*K}

Now that we have all of our values, let's plug them into the equation (I'll be excluding units for simplicity but they cancel out to leave units of torr in the answer)

P=\frac{(.99)(62.36)(305)}{4.50}\\P=4184.36

P=4184.36 torr

<em>Very briefly</em>, I don't know what your periodic table looks like, but mine has nitrogen's molar mass as 14.01. If you have a different mass of nitrogen, this pretty drastically impacts the value. For example, if your nitrogen's molar mass was rounded to 14.0 (making N2 28g) then it would be one mole instead of .99 moles, raising the answer to 4228.70 torr. If you have any different values just plug them in in their proper spots. A similar concept applies to the Kelvin conversion.

6 0
3 years ago
What is the concentration of H3O ions in pure water?
notka56 [123]

Answer:

The answer is 10-7M

Explanation:

7 0
3 years ago
Insoluble molecular compounds break apart into atoms when added to water.<br> True<br> O False
masha68 [24]

Answer:

False.

This is false because, no chemical reaction could possibly happen.

But in case of sodium it is highly reactive with water.......... so there will be a chemical reaction.

but as sodium is not a insoluble molecular compound this is not applicable to the situation.

8 0
3 years ago
Please help with what equation and what numbers to plug in, I can do the rest.
ohaa [14]
20 protons it takes for the answer
8 0
4 years ago
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