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Irina-Kira [14]
3 years ago
14

Corey thinks of a number. He adds 25 to it then halves the result. Then he subtracts 17 and multiplies the result by 3. His fina

l answer is 18.
Mathematics
2 answers:
faltersainse [42]3 years ago
5 0
You just have to do the opposite of what he did.
So (18 ÷3 +17) ×2 -25 

The final answer is 21
scoray [572]3 years ago
4 0
You just have to do the opposite of what Corey did.
So (18 ÷3 +17) ×2 -25

The answer is 21

Hope I can help you, brainliest answer? :)
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The sequence an= -(3)" - 1 is graphed below:
Pani-rosa [81]

Answer:

The given sequence is:

a(2)=1

a(3)=3

a(4)=9

We are to find the average rate of change between n=3 and n=4 for the given function.

Average rate of change = 

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Step-by-step explanation:

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Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

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Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

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Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

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3 years ago
Identify the equation of a line in slope-intercept form that is parallel to y = 2.5x + 5 and passes through (2, 3).
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Answer:

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Step-by-step explanation:

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