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oksian1 [2.3K]
3 years ago
12

Two long, parallel wires are attracted to each other by a force per unit length of 350 µN/m. One wire carries a current of 22.5

A to the right and is located along the line y = 0.420 m. The second wire lies along the x axis. Determine the value of y for the line in the plane of the two wires along which the total magnetic field is zero.
Physics
1 answer:
pishuonlain [190]3 years ago
3 0

Answer

given,

force per unit length = 350 µN/m

current, I = 22.5 A

y = y = 0.420 m

\dfrac{F}{L}= \dfrac{KI_1I_2}{d}

I_2 = \dfrac{F}{L}\dfrac{d}{KI_1}

I_2 = 350\times 10^{-6}\times \dfrac{0.42}{2 \times 10^{-7}\times 22.5}

    I₂ = 32.67 A

distance where the magnetic field is zero

\dfrac{4\pi \times 10^{-7}\times 32.67}{2\pi y_1}=\dfrac{4\pi \times 10^{-7}\times 22.5}{2\pi (0.42-y_1)}

y_1 = 0.248\ m

there the distance at which the magnetic field is zero in the two wire is at 0.248 m.

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3 years ago
The stopping distance d of a car after the brakes are applied varies directly as the square of the speed r. If a car travelling
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270/70^2  = x/80^2

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270 (6400) = 4900x   

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Hope this helps


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Ice of mass 5 g at 0 °C melts to water at 0 °C.
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A person doing chin-up weighs 700.0 N, disregarding the weight of the arms. During the first 25.0 cm of the lift, each arm exert
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First, we will get the resultant force:
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weight of person = 700 newton

Assume that the force exerted by the arms has a vertically upwards direction.
Force exerted by arms = 2*355 = 710 newtons

Therefore, the resultant force = 710 - 700 = 10 newtons (in the vertically upwards direction) 

Now, we will get the mass of the person.
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Then we will calculate the acceleration of the resultant force:
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Finally, we will use the equation of motion to get the final speed of the person.
V^2 = U^2 + 2aS where:
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S is the distance covered = 25 cm = 0.25 meters

Substitute with the givens in the above equation to get the final speed as follows:
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Based on the above calculations:
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4 0
3 years ago
Read 2 more answers
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