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3 years ago

52.13 dg = ___________ mg someone please help me

Physics

2 answers:

NNADVOKAT [17]3 years ago

8 0

5213 mg is the answer

dmitriy555 [2]3 years ago

5 0

Answer:

5,213mg

Explanation:

So, there are multiple ways to convert the different metric units, but I am going to explain how I was taught in elementary school, since it's the most simplest explanation.

To start off with, you want to memorize this saying:

King Henry Died By Drinking Chocolate Milk

Each beginning letter stands for a different metric unit.

Kilo, Hecto, Deka, Base, Deci, Centi, Milli

Base stands for your base, for instance, meter, gram, and liter would be considered your base units.

dg stands for Decigram, and mg stands for Milligram.

Then, you want to write this out:

KHDBDCM

If you can remember that saying above, writing these letters should be easier.

Once you write that down, you need to draw an arrow from each letter, starting from the second D, since the second D stands for Deci. You will stop the arrow at M since M stands for Milli.

The arrow should look something like the picture attached.

Count how many bumps the arrow does. There are 2 in total.

You then move your decimal 2 places to the right, since that's where the arrow is going.

52.13dg = 5,213mg

Remember that the decimal is invisible once it becomes a whole number. So, the decimal isn't necessary.

In conclusion, the answer is 5,213mg.

I hope this helped, have a good day!

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A 0.12 g honeybee acquires a charge of +24pC while flying. The earth's electric field near the surface is typically 100 N/C, dow

shusha [124]

Answer:

150000000

$\dfrac{F_e}{F_g}=0.00000203873598369$

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Explanation:

q = Charge = 24 pC

m = Mass of honeybee = 0.12 g

E = Electric field = 100 N/C

g = Acceleration due to gravity = 9.81 m/s²

$1\ C=6.25\times 10^{18}\ electrons$

Number electrons is

$n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000$

The number of electrons added or removed was 150000000

Force is given by

$F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N$

The ratio is

$\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369$

The ratio is $\dfrac{F_e}{F_g}=0.00000203873598369$

Balancing the forces we get

$Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C$

The electric field required is 49050000 N/C

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Explanation:

One of the applications of radioactive decay is the dating of different systems.

To do this, the quantity of radioactive material in a meter is determined and with the average life time, the time of the sample is found.

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147Sm T ½ = 1.06 1011 years

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we already have the half-life of the different elements given

a) meteors. As these decomposed in the formation of the solar system, their life time is around 3 109 to 5 109 years, so it is necessary to look for elements that have a life time of this order, among the candidates we have 238U, 40K and 87Rb if these elements were at the moment of the formation of these meteors, there must still be rations in them, instead elements 14C already completely adequate

b) rock. The formation period is 4.20-108 years, therefore one of the most promising elements is 235U and to a lesser extent 40K since it is more abundant in rocks. The other elements with higher life times have not decayed and therefore will not give a true value and the 14C is completely decayed

c) volcanic ash. Formation time 6107 years, the only element that has the possibility of having a count is the 235U, the others have a life time so long that they have not decayed and the 14C is complete, unbent

d) scarp of an earthquake formation time 5 101 years, The only one that has any possibility is 14C even when it has declined very little, all the others, you have time to long that has not decayed

e) INCA excavation. The time of this civilization is about 10000 to 500 years (104 to 5 102 years), we see that this period would be ideal for 14C since it has some period of cementation, the others have not decayed

f) Tree in Blepharitis. 14C should be used since it is the one with the least average life time, even though the measurements must be very careful because of a period of disintegration. We have such a long time that they have not decayed

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