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3 years ago

Which of the following factors determines the strength of the frictional force between two surfaces

Physics

1 answer:

Juli2301 [7.4K]3 years ago

6 0

Answer:

Explanation:

The strength of the force of friction depends on two factors: how hard the surfaces push together and the types of surfaces involved. What factors affect the gravitational force between two objects? Two factors affect the gravitational attraction between objects: mass and distance.

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6. If a vehicle needs 5s to complete 15m. Find the mean speed of it?

Karolina [17]

Answer:

3m/s

Explanation:

Time=5s

Distance =15m

Speed=distance/time

Putting the values

Speed=15m/5s

Speed=3m/s is the answer

Hope it will help you. :)

4 0

2 years ago

A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 14 m/s. A passenger accidentally drops his camera fr

fgiga [73]

Answer:

<em>The balloon is 66.62 m high</em>

Explanation:

<u>Combined Motion </u>

The problem has a combination of constant-speed motion and vertical launch. The hot-air balloon is rising at a constant speed of 14 m/s. When the camera is dropped, it initially has the same speed as the balloon (vo=14 m/s). The camera has an upward movement for some time until it runs out of speed. Then, it falls to the ground. The height of an object that was launched from an initial height yo and speed vo is

$\displaystyle y=y_o+v_o\ t-\frac{g\ t^2}{2}$

The values are

$\displaystyle y_o=15\ m$

$\displaystyle v_o=14\ m/s$

We must find the values of t such that the height of the camera is 0 (when it hits the ground)

$\displaystyle y=0$

$\displaystyle y_o+v_o\ t-\frac{g\ t^2}{2}=0$

Multiplying by 2

$\displaystyle 2y_o+2v_ot-gt^2=0$

Clearing the coefficient of $t^2$

$\displaystyle t^2-\frac{2\ V_o}{g}\ t-\frac{2\ y_o}{g}=0$

Plugging in the given values, we reach to a second-degree equation

$\displaystyle t^2-2.857t-3.061=0$

The equation has two roots, but we only keep the positive root

$\displaystyle \boxed {t=3.69\ s}$

Once we know the time of flight of the camera, we use it to know the height of the balloon. The balloon has a constant speed vr and it already was 15 m high, thus the new height is

$\displaystyle Y_r=15+V_r.t$

$\displaystyle Y_r=15+14\times3.69$

$\displaystyle \boxed{Y_r=66.62\ m}$

3 0

2 years ago

Charges of +5C and −9C are at a distance of 1m from each other. Which diagram represents the force between the two charges?

weqwewe [10]

the answer is CCCCCCCCCCCCCCCCC

8 0

3 years ago

Read 2 more answers

The principal of uniformitarian states that

Akimi4 [234]

It started that the present is the key to the past. The process that we see in operation today are the same ones that have operated in the geologic past.

4 0

3 years ago

What is the final concentration of DD at equilibrium if the initial concentrations are [A][A]A_i = 1.00 MM and [B][B]B_i = 2.00

pentagon [3]

Answer:

A) Concentration of A left at equilibrium of we started the reaction with [A] = 2.00 M and [B] = 2.00 M is 0.55 M.

B) Final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M is 0.90 M.

[D] = 0.90 M

Explanation:

With the first assumption that the volume of reacting mixture doesn't change throughout the reaction.

This allows us to use concentration in mol/L interchangeably with number of moles in stoichiometric calculations.

- The first attached image contains the correct question.

- The solution to part A is presented in the second attached image.

- The solution to part B is presented in the third attached image.

8 0

3 years ago