Question

What is the quotient: (72y3 + 12y2 – 30y) ÷ 6y ? need help dividing.

Answer 1

Answer:

$12y^{2}+2y-5$

Step-by-step explanation:

we know that

$(72y^{3}+12y^{2}-30y)/6y=(\frac{72y^{3}}{6y})+( \frac{12y^{2}}{6y})-(\frac{30y}{6y} )$

Simplify

$12y^{2}+2y-5$

Answer 2

The simplification of the function  (72y3 + 12y2 – 30y) ÷ 6y can be determined by getting the least factor in which the two polynomials in the numerator and denominator have. Numerator is divisible by 6y. The variables' power is decreased by 1. Hence the answer is 12y2 + 2y – 5.