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natta225 [31]
4 years ago
15

Can i get local search results based on my location

Computers and Technology
1 answer:
almond37 [142]4 years ago
8 0
Yes, your search results are based on your location, if you allow safari to use your location (phone)
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the username you feel like using

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What is the biggest decision you think you will make in your lifetime? Explain why you think it would be such a big decision.
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Having kid will be the biggest thing ever ever
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Plzz helps me with hw
IceJOKER [234]

Answer:

1. not statistical

2. statistical

3. statistical

4. not statistical

5. statistical

6. not statistical

7. statistical

Explanation:

The statistical can compare more then 1 thing to make it reasonable.

4 0
4 years ago
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
Why are you getting rid of comments? I saw a message saying that. (Psst. The reason why it's Computers &amp; Technology is I did
Hunter-Best [27]

Answer:

what?

Explanation:

........................

6 0
3 years ago
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