The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is 
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now, 
We know that the sum of probability of an event and its complement is 1.
So, 
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
Answer:
-2x
Step-by-step explanation:
Graph
y > −2x + 3
Use the slope-intercept form to find the slope and y-intercept.
The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
y = mx + b
Find the values of m and b using the form y = mx + b. m = −2
b = 3
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: −2
intercept: (0, 3)
Graph a dashed line, then shade the area above the boundary line since y is greater than
−2x + 3.
y > −2x + 3
Answer:
Step-by-step explanation:
1l ........8.5 miles
x l .......6 miles
-----------------------
x=6*1/8.5
x=0.70 l
2*0.7=1.4 l petrol/day ( to work and come back home)
5*1.4=7 l/week ( 5 days works in a week)
7*1.26=8.82 L /week
8.82>8.5
The petrol costs more
So the answer is NO
Try this solution, it consists of two parts (MN=8).
Answer:
32ft by 20ft
Step-by-step explanation:
8x4 and 5x4