And angle is formed by the union of two vertices or corners.
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The <u><em>correct answer</em></u> is:
0.6 + 0.02 + 0.004
Explanation:
To write a number in expanded form, we use place value. In this number, 6 is in the tenths place; that makes its value 6(0.1) = 0.6.
2 is in the hundredths place; that makes its value 2(0.01) = 0.02.
4 is in the thousandths place; that makes its value 4(0.001) = 0.004.
Together, we get a sum of 0.6+0.02+0.004.
Answer:

Step-by-step explanation:
Let
d ------> the number of days
c -----> the cost
we know that
The cost is equal to the number of days multiplied by $2 per day plus the initial fee of $5
The linear equation in slope-intercept form is

where
m is the slope
b is the c-intercept (value of c when the value of d is equal to zero)
in this problem we have
m=$2 per day
b=$5
substitute

Answer:
The first fraction is between 27 and 28, closer to 28. The second fraction is between 3 and 4, closer to 4. Compatible numbers in division are numbers that can be divided mentally. 28 divided by 4 is 7. The quotient will be around 7.
Step-by-step explanation:
Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

For parts (a) and (b), you're given everything you need to determine

.
For part (c), if

and

are mutually exclusive, then

, so

. If the given probability is

, then you can find

. But if this given probability is for the intersection, finding

is impossible.
For part (d), if

and

are independent, then

.