Answer:
2 complex conjugates
Step-by-step explanation:
The discriminate is the part of the quadratic formula that is under the radical sign. If the discriminate is negative, that means that the solutions, both of them, are complex conjugates, aka imaginary solutions.
473 would be it because you can simplify it into fraction then you can do it by 1 so the answer is 473 or 374
6 - 1/2z = 2/3
subtract 6 from both sides
- 1/2z = -16/3
divide both sides by -1
1/2z = 16/3
rewrite
1z/2 = 16/3
multiply both sides by 2
1z = 32/3
z = 32/3 or 10 2/3
Hope this helps :)
Answer:
Step-by-step explanation:
x-y=7
-3x+9y=-39
Divide the second equation by 3
-x +3y = -13
Add this to the first equation
x-y=7
-x +3y = -13
----------------------
0x +2y = -6
Divide by 2
2y/2 = -6/2
y = -3
Now find x
x-y = 7
x -(-3) = 7
x+3 = 7
Subtract 3 from each side
x = 4
(4,-3)
Or by substitution
x-y=7
solve for x
x = 7+y
-3x+9y=-39
Substitute y+7 in for x
-3(7+y) +9y = -39
Distribute
-21 -3y +9y = -39
Combine like terms
-21 +6y = -39
Add 21 to each side
6y = -18
4.
4^3 = 64
64X64 = 4096
4^6 = 4096
