the possible solutions of this equation. Is that they are not real.
The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere. Given that the volume of any sphere is:
V=(4πr^3)/3 The space between to sphere of different radius and positioned about the same center is:
S=(4πR^3)/3-(4πr^3)/3 I used S=volume of space, R=larger radius and r=smaller radius...
S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so
S=(4π/3)(5^3-4^3)
S=(4π/3)(125-64)
S=(4π/3)(61)
S=244π/61
S=4π cm^3
S≈12.57 cm^3 (to nearest hundredth of a ml)
Order set...{160,165,170,240,240,450}
The "mean" is the arithmetic average of the elements...
mean=(160+165+170+240+240+450)/6=237.5
The "median" if the set has an odd number of terms is the middle term, if the set has an even number of terms, it is the average of the middle two terms.
In this case the number of elements is even and the middle two terms are 170 and 240 so:
median=(170+240)/2=205
The "mode" is the term which appears the most in the set, so in this case:
mode=240
3.2355
Fist we line up all the numbers, we forget about the decimal for a moment and we will come back to it in the end.
7.19
x0.45
----------
28760
We put 0 first because we are working on the ten place, and we do a normal multiplication problem: 4*9= 36 (bring the 3 over). 4*1= 4+3 = 7. 4*7= 28 Then we work on the second part.
7.19
x0.45
----------
<span> 28760
</span> <span>3555
</span>
As same as the first step, it is normal multiplication...
7.19
x0.45
----------
28760
<span>3555
</span>-----------
32315
We all both numbers together... For the final answer, we count the decimal place of the numbers given in the problem, 7.19 and 0.45. They both have 2 decimal places, so 2+2=4. So 4 decimal places. We give the final answer 4 decimal places.
3.2315
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Try A and see if it works but im not sure
