
The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is

.
So the desired probability is
Answer:
y = -4x - 7
Step-by-step explanation:
we use the slope intercept formula given by; y = mx + b
b = y intercept, which is when x = 0
m = slope
so they tell us the slope.. we just need to find b - the y intercept.
y = mx + b
plug in your coordinates (-2,1)
1 = -4(-2) + b
1 = 8 + b
1 - 8 = b
-7 = b
put it all together.
y = -4x - 7
<span> You must make it a fraction by multiplying by 100, moving the decimal over by 2 spaces right so we have 36. Then, put it over 100, because it is a fraction. Now, with 36/100 we must simplify by dividing each number by another # that goes into it evenly, such as 2. We get 18/50, reduce by 2, we get 9/25. There you go hope I helped </span>
Answer:
The Taylor series of f(x) around the point a, can be written as:
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Here we have:
f(x) = 4*cos(x)
a = 7*pi
then, let's calculate each part:
f(a) = 4*cos(7*pi) = -4
df/dx = -4*sin(x)
(df/dx)(a) = -4*sin(7*pi) = 0
(d^2f)/(dx^2) = -4*cos(x)
(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4
Here we already can see two things:
the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.
so we only will work with the even powers of the series:
f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....
So we can write it as:
f(x) = ∑fₙ
Such that the n-th term can written as:
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