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3 years ago

Prism A is similar to Prism B. The volume of Prism A is 2720 cm³.

Mathematics

1 answer:

Novay_Z [31]3 years ago

4 0

I think that we need more information, but we could just try ratios:
8 is to 2720 as 4 is to x
8/2720 = 4/x
x = 1360

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The oblique pyramid has a square base. What is the volume of the pyramid? 2.5 cm3 5 cm3 6 cm3 7.5 cm3

Olenka [21]

Take a look at the attachment below. It fills in for the attachment that wasn't provided in the question -

An oblique pyramid is one that has a top not aligned with the base. Due to this, the height of the pyramid connects with two vertices at its ends to form a right angle present outside the pyramid, knowing that it is always perpendicular to the base. There is no difference between the calculations of the volume of an oblique pyramid and a pyramid however -

$\\Base Area = 2 cm * 2 cm = 4 cm^2,\\Volume ( Pyramid ) = 1 / 3 * ( Base Area ) * ( Height ),\\Volume = 1 / 3 * ( 4 ) * ( 3.75 ),\\-------------------------\\Volume = 5 cm^3$

And thus, you're solution is 5 cm^3, or in other words option b!

3 0

3 years ago

If the diagonals of a parallelogram are congruent and are perpendicular bisectors of each other than what is it

alexira [117]

The parallelogram is a square

5 0

3 years ago

A baker is building a rectangular solid box from cardboard to be able to safely deliver a birthday cake. The baker wants the vol

k0ka [10]

The length of the rectangular delivery box must be equal to 4 inches.

Let the length of the box be L.

Let the width of the box be W.

Let the height of the box be H.

Given the following data:

Volume of box = 224 cubic inches.

Translating the word problem into an algebraic expression;

$W = 3 + L$ ......equation 1

$H = 4 + L$ ......equation 2.

Mathematically, the volume of a rectangular solid is given by the formula;

$Volume = length * width * height$ .....equation 3.

Substituting the values into equation, we have;

$224 = L * (3 + L) * (4 + L)\\\\224 = (3L + L^{2})* (4 + L)\\\\224 = 12L + 3L^{2} + 4L^{2} + L^{3} \\\\224 = 12L + 7L^{2} + L^{3}$

Rearranging the polynomial, we have;

$L^{3} + 7L^{2} + 12L - 224 = 0$

We would apply the remainder theorem to solve the polynomial.

According to the remainder theorem, if a polynomial P(x) is divided by (x - r) and there is a remainder R; then P(r) = R.

When x = 3

$(x - 3) = 0\\x = 3$

$P(3) = 3^{3} + 7(3^{2}) + 12(3) - 224\\\\P(3) = 27 + 7(9) + 36 - 224\\\\P(3) = 27 + 63 + 36 - 224 = -98 \neq 0$

We would try with 4;

$P(4) = 4^{3} + 7(4^{2}) + 12(4) - 224\\\\P(4) = 64 + 7(16) + 48 - 224\\\\P(4) = 64 + 112 + 48 - 224\\\\P(4) = 224 - 224 = 0$

Therefore, 4 is one of its roots.

Hence, the length of the rectangular delivery box must be equal to 4 inches.

Find more information on polynomial here: brainly.com/question/10689855

3 0

3 years ago

Someone please tell me and maybe ill pay you

rjkz [21]

4x = 6x -10
2x = 10
x = 5

answer
x = 5

6 0

4 years ago

An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining.

Tanya [424]

Answer:

98% Confidencce Interval is ( 3030.6, 7467.4 )

Step-by-step explanation:

Given that:

Sample size $n_1 =$ 71

Sample size $n_2 =$ 31

Sample mean $\overline x_1 =$ 41628

Sample mean $x_2 =$ 36,379

Population standard deviation $\sigma_1$ = 4934

Population standard deviation $\sigma_2 =$ 4180

At 98% confidence interval level, the level of significcance = 1 - 0.98 = 0.02

Critical value at $z_{0.02/2} = 2.33$

The Margin of Error = $z \times \sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2} }$

= $2.33 \times \sqrt{\dfrac{4934^2}{71}+\dfrac{4180^2}{31} }$

= $2.33 \times \sqrt{\dfrac{24344356}{71}+\dfrac{17472400}{31} }$

= $2.33 \times \sqrt{906504.06 }$

= 2218.40

The Lower limit = $( \overline x_1 - \overline x_2) - (Margin \ of \ error)$

= ( 41628 - 36379 ) - ( 2218.40)

= 5249 - 2218.40

= 3030.6

The upper limit = $( \overline x_1 - \overline x_2) + (Margin \ of \ error)$

= ( 41628 - 36379 ) + ( 2218.40)

= 5249 + 2218.40

= 7467.4

∴ 98% Confidencce Interval is ( 3030.6, 7467.4 )

5 0

4 years ago