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Ksenya-84 [330]
3 years ago
5

7(x+4)-2[x-3(5+x)]=⅔(x-6)​

Mathematics
1 answer:
aev [14]3 years ago
6 0

Answer:

7(x+4)-2/3 (x-6) < 2[x-3(x+5)]

Do it 1 step at a time.

7(x+4)-2/3 (x-6) < 2[x-3x-15]

7x+28 - 2/3 (x-6) < 2[x-3x-15]

I'll assume you mean (2/3)*x-6)

---

7x+28 - (2x/3) - 4 < 2[-2x-15]

7x+24 - (2x/3) < -4x-30

Add 4x

11x+24 - (2x/3) < -30

Add 30

11x + 54 - (2x/3) < 0

Multiply thru by 3

33x + 162 - 2x < 0

31x < 162

x < 162/31

Step-by-step explanation:

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*below is an explanation! :)

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Watch this!

Let's take 10 for example. 10 is greater than 0 like x>0 requires!

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Now let's take a random number that satisfies 0> x and do the same as we did above!

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3 years ago
It would be appreciated if there could be an explanation along the answer
soldi70 [24.7K]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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