7(x+4)-2[x-3(5+x)]=⅔(x-6)
1 answer:
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Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:
<em>y</em> = -1 - <em>x</em> ==> <em>x</em> = -1 - <em>y</em>
<em>y</em> = <em>x</em> - 1 ==> <em>x</em> = 1 + <em>y</em>
So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.
This means the area is given by the integral,
The integral with respect to <em>x</em> is trivial:
For the remaining integral, integrate term-by-term to get
Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.
Answer:
4,099 and 5,011
Step-by-step explanation:
This problem can be solved by taking options one by one.
Option (1) : 4,099
Digit in ones place = 9
The value of the digit in tens place = 90
. It is correct.
Option (2) : 4,110
Digit in one places = 0
The value of the digit in tens place = 10
It is incorrect.
Option (3) : 5,909
Digit in one places = 9
The value of the digit in tens place = 0
It is again incorrect.
Option (4) : 5,011
Digit in one places = 1
The value of the digit in tens place = 10
. It is correct.
Hence, in option (a) and (d), the he ones place is 1/10 the value of the digit in the tens place.