7(x+4)-2[x-3(5+x)]=⅔(x-6)
1 answer:
Answer:
7(x+4)-2/3 (x-6) < 2[x-3(x+5)]
Do it 1 step at a time.
7(x+4)-2/3 (x-6) < 2[x-3x-15]
7x+28 - 2/3 (x-6) < 2[x-3x-15]
I'll assume you mean (2/3)*x-6)
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7x+28 - (2x/3) - 4 < 2[-2x-15]
7x+24 - (2x/3) < -4x-30
Add 4x
11x+24 - (2x/3) < -30
Add 30
11x + 54 - (2x/3) < 0
Multiply thru by 3
33x + 162 - 2x < 0
31x < 162
x < 162/31
Step-by-step explanation:
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E would be your answer because the two negatives become a positive
AB=9
AC=`12
BC=x=?
ABC is a triangle with 90 degree
x2=(9)2+(12)2
x2=81+144
x2=225
x=15 so the distance between the points given is 15
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24
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and surely you'd know what the roots are
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3.4 is the answer i think
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