You already have the answer in the question
Y=ln(ln(x))
y'=(1/x)/Ln(x)=1/xln(x)
Answer:
2
Step-by-step explanation:
f(x)=x^2+1
now,
f(1)=1^2+1
=1+1
=2
<span>The answer to this question is c, two. The top arc of the circle intersects the y=x^2 as each 'limb' extends into infinity. The part of the circle below the x-axis does not intersect the circle. The y=x^2 curve does not dip below the x-axis, but does extend into infinity on both the negative x-axis and positive x-axis.</span>
Answer:
50
Step-by-step explanation: