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kenny6666 [7]
3 years ago
9

Peyton received a graduation gift from his grandparents of $12,700. He

Mathematics
1 answer:
arlik [135]3 years ago
7 0

Answer:

Peyton's account will have $13,842.18 after a year.

Step-by-step explanation:

Given that Peyton received $ 12,700 and decided to invest it for a year in an account that grants an interest of 8.8% per year, compounded semiannually, to determine the amount of money that will be in said account after the passage of one year, it is necessary to perform the following calculation:

X = 12,700 (1 + 0.088 / 2) ^ 1x2

X = 13,842.18

Therefore, after a year has passed, Peyton's account will be $ 13,842.18.

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Plz answer question in screen shot
Andre45 [30]

Answer: 342.32

Step-by-step explanation: sin(25) = h/a

Sin(25)= h/27

27*sin(25) = h

b*h = area

6 0
3 years ago
Find the median of the data.<br> 12, 33, 18, 28, 29, 12, 17, 4, 2<br> The median is
Reptile [31]

Answer:

The median is 29

Step-by-step explanation:

So you have to cross out 12 then 2 then 33 then 4 then 18 then 17 then 28 then 12 and the last number that's standing is 29.

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3 years ago
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What is 3.96 × 0.4, please help me ​
Kisachek [45]

Answer:

1.584

Step-by-step explanation:

1.584 = 3.96 × 0.4

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4 years ago
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sydney planted 5/9 of her fall flowers.she had 63 unplanted flowers to start.how many flowers does she have left to plant.?how m
PilotLPTM [1.2K]
35. 

5/9= 0.555555556

0.55555556*63=35

2/3= 0.6666666667

0.666666667*63= 42

63-35=28

42-28=14
She has 35 unplanted flowers and must plant 14 more in order to have filled 2/3 of her flower bed. 




8 0
3 years ago
HELLOOOO HELP PLEASE
MA_775_DIABLO [31]

Answer:

2*log(x)+log(y)

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

   log_ba^c=c*log_ba

   So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: log_ba=x\implies b^x=a

   Now if we raise both sides to the power of c, we get the following equation: (b^x)^c=a^c

   Using the exponential identity: (x^a)^c=x^{a*c}

    We get the equation: b^{xc}=a^c

    If we convert this back into logarithmic form we get: log_ba^c=x*c

    Since x was the basic logarithm we started with, we substitute it back in, to get the equation: log_ba^c=c*log_ba

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

    log_b{ac}=log_ba+log_bc

    Now for a quick proof, let's just say: x=log_ba\text{ and }y=log_bc

    Now rewriting them both in exponential form, we get the equations:

    b^x=a\\b^y=c

    We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

    b^x*b^y=a*c

   Using the exponential identity: x^{a}*x^b=x^{a+b}, we can rewrite the equation as:

 

   b^{x+y}=ac

   taking the logarithm of both sides, we get:

   log_bac=x+y

   Since x and y are just the logarithms we started with, we can substitute them back in to get: log_bac=log_ba+log_bc

Now let's use these identities to rewrite the equation you gave

log(x^2y)

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

log(x^2)+log(y)

Now using the logarithm of a power to rewrite the log(x^2) we get:

2*log(x)+log(y)

3 0
2 years ago
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