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AlladinOne [14]
3 years ago
14

If 0° ≤ θ ≤ 90° and cosθ = 11 15 , what is the value of sin (90° - θ)?

Mathematics
2 answers:
Tresset [83]3 years ago
7 0

Since the angles θ and 90° - θ are complementary, the cosine of one of the angles is equal to the sine of the other. Therefore, because cosθ = \frac{11}{15}, the value of sin (90° - θ) must be \frac{11}{15}.

kolezko [41]3 years ago
5 0
The same value as cosα

cosα=sin(90-α) and vice versa

sinα=cos(90-α)
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