The legs are the sides that form the right angle in a right triangle true or false

A recently negotiated union contract allows workers in a shipping department 24 minutes for rest, 10 minutes for personal time,

Alik [6]

Answer:7.125 min

Step-by-step explanation:

Given

Resting time =24 min

Personal time=10 min

Delay=14 min

Observed Time=6min/cycle

Performance Rating=95%

Allowance Time=Rest time+Personal time+delay

Allowance time=24+10+14=48 min

$Allowance %=\frac{Allowance Time}{Total Time}=\frac{48}{4\times 60}=20 \%$

Allowance Factor= $\frac{1}{1-0.20}=\frac{5}{4}$

Calculate the Normal Time

Normal time=Observed time $\times$ personal Time=6\times 0.95=5.7 min

Standard time=Normal time $\times$ Allowance Factor

Standard time = $NT\times Allowance factor=5.7\times 1.25$ =7.125 min

3 0

3 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

See comment for complete question.

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

7 0

2 years ago

A phone company offers to monthly plans. Plan a cost $23 plus an additional $.08 for each minute of calls. Plan B cost $19 an ad

Anettt [7]

Answer:

The indifference point is 100 minutes.

Step-by-step explanation:

Giving the following information:

Plan a cost $23 plus an additional $.08 for each minute of calls.

Plan B cost $19 an additional $.12 for each minute of calls.

First, we need to establish the total cost formula for each plan:

Plan A= 23 + 0.08*x

Plan B= 19 + 0.12*x

x= number of minutes

Now, to calculate the indifference point, we equal both formulas and isolate x:

23 + 0.08x = 19 + 0.12x

4 = 0.04x

100= x

The indifference point is 100 minutes.

Prove:

Plan A= 23 + 0.08*100= $31

Plan B= 19 + 0.12*100= $31

5 0

3 years ago

URGENT!! WILL MARK BRAINLIEST IF CORRECT!!!

kow [346]

Answer:

Story 2 because it is talking about how much they spend. ANOTHER HINT: That equation has all the numbers in story 2. They key is to look at how the problem is set up.

6 0

3 years ago

A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co

lisov135 [29]

Answer:

The complete solution and step by step explanation is written below.

Note:

Here is the complete question you were probability asking as you may have unintentionally missed to mention the parts (a) and (b). So, after a little research, I figured out that this was probably the complete question you had meant to ask. So, I am answering based on the reference of this complete question that may indeed clear your concepts.

Complete Question:

A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I costs $2.40 per gallon, and milk from dairy II costs $0.80 per gallon. At most $144 is available for purchasing milk. Dairy I can supply at most 50 gallons averaging 3.9% butterfat, and dairy II can supply at most 80 gallons averaging 2.9% butterfat. Answer parts a and b.

A. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of butterfat? (Also, what IS the maximum amount of butterfat?)

B. The solution from part A leaves both dairy 1 and dairy 2 with excess capacity. Calculate the amount of additional milk each dairy could produce.

Step-by-step explanation:

Let A be number of gallons of the amount of milk the company bought from Dairy 1.

(100 - X) be the number of gallons of the amount of milk the company bought from Dairy 2.

Milk from dairy I costs $2.40 per gallon and milk from dairy II costs $0.80 per gallon.

So, the equation of total cost available for purchasing the milk be:

Cost = 2.40A + ( 100 - A)0.80

As $144 is the total cost available for purchasing the milk.

Hence, Cost equation would be as follows:

Cost = 2.40A + ( 100 - A)0.80

144 = 2.40A + ( 100 - A)0.80

144 = 2.40A + 80 - 0.80A

1.6A = 64

So, A = 64 ÷ 1.6

= 40 gallons

Calculation of gallons of Dairy 1 and Dairy 2:

gallons of Dairy 1 ⇒ A = 40 gallons

gallons of Dairy 1 ⇒ 100 - A = 100 - 40 = 60 gallons

The equation for Fat will be:

Fat for dairy 1 = 40 × 3.9% = 1.56

Fat for dairy 2 = 60 × 2.9% = 1.74

ADD = 1.56 + 1.74 = 3.3 %

Calculation Part B:

Dairy 1 will have = 50 - 40 = 10 gallons ( excess)

Dairy 2 will have = 80 - 60 = 20 gallons (excess)

Keywords: word problem, equation solving

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5 0

3 years ago