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3 years ago

PLEASE ANSWER FAST THIS IS VERY IMPORTANT!!!!! I NEED TO KNOW HOW TO SOLVE #7 PLEASE PLEASE HELP

Mathematics

2 answers:

gavmur [86]3 years ago

7 0

It might me x=7 check my answer have not did geometry recently

Pani-rosa [81]3 years ago

6 0

If the pencil markings are correct, LM=NP.
This means that both lines should be the same length (you've marked them as congruent). Therefore, you can set the two equations equal to one another.
3x=5x-14
You should get a solution of x=7. If you have trouble with that, comment. I was lazy and did it with my graphing calculator, but I can show you how to do it algebraically.

From the drawing, assuming your congruency markings are correct, K is the midpoint of LM. Therefore, LK will be half the length of LM.
As LM looks like it equals 3x, LK would be 3x/2. In the above step, I found that x=7. Plug x unto the equation 3x/2 to get 21/2, which is your final answer.

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Evaluate the function f(x)=2x-2, when x=-1

sertanlavr [38]

Substitute -1 for the variable x.

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2 years ago

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Answer:

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If the U.S> adopts the SI standard for letter-sized paper, both the width and length of standard paper will have to be increased. Therefore letter-sized paper will occupy a larger area and will be heavier if the thickness and density do not change.

Step-by-step explanation:

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2 years ago

I need help qucikly whats the answer??

Anni [7]

Answer:

Step-by-step explanation:

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2 years ago

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Two angles are complementary. The measure of the larger angle is 10 more than 4 times the measure of the small angle. Find the m

eimsori [14]

Answer:

Step-by-step explanation:

Let the measurement of the smaller angle = x

Larger angle = 4x + 10

x + (4x + 10) = 90 {complementry}

5x + 10 = 90

5x = 90 -10

5x = 80

x = 80/5

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2 years ago

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What is the standard form of the equation of the circle x^2 - 4x +y^2 +6y + 4 = 0 ?

dybincka [34]

Answer: (x-2)^2+(y+3)^2 = 9

Side notes
1) This circle has a center of (2,-3)
2) The radius of this circle is 3
3) The graph is shown in the attached image

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Work Shown:

x^2-4x+y^2+6y+4=0
x^2-4x+y^2+6y+4-4=0-4
x^2-4x+y^2+6y = -4
x^2-4x+4+y^2+6y = -4+4 ... see note 1 below
(x^2-4x+4)+y^2+6y = 0
(x-2)^2+y^2+6y = 0
(x-2)^2+y^2+6y+9 = 0+9 ... see note 2 below
(x-2)^2+(y^2+6y+9) = 9
(x-2)^2+(y+3)^2 = 9

note 1: I'm adding 4 to both sides to complete the square for the x terms. You do this by first taking half of the x (not x^2) coefficient which in this case is -4. So take half of -4 to get -2. Then square this result to get 4

note 2: Like with note 1, I'm completing the square. What's different this time is that this is for the y terms now. The y coefficient is 6. Half of this is 3. Square 3 to get 9. So this is why we add 9 to both sides.

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So the equation in standard form is (x-2)^2+(y+3)^2 = 9

Note how
(x-2)^2+(y+3)^2 = 9
is equivalent to
(x-2)^2+(y-(-3))^2 = 3^2

So that second equation listed above is in the form (x-h)^2+(y-k)^2 = r^2
where
h = 2
k = -3
r = 3

making the center to be (h,k) = (2,-3) and the radius to be r = 3

The graph is attached.

5 0

2 years ago