Find the missing length in the right triangle. If necessary, round to the nearest tenth.

Show equation has a slope of -3 and a y-intercept of 8

Anvisha [2.4K]

Answer:

y=-3x+8

Step-by-step explanation:

8 0

3 years ago

Ken has a pole that is 26 inches long. He wishes to cut it into two pieces so that one piece will be 8 inches longer than the ot

Yuliya22 [10]

Answer:

9 inches

Step-by-step explanation:

Do the question algebraically, represented by this equation:

let x be the shorter piece

x + (x + 8) = 26 (longer piece is 8 units longer)

Remove brackets

x + x + 8 = 26 Combine like terms

2x + 8 = 26 Start isolating "x"

2x + 8 - 8 = 26 - 8 Subtract 8 from both sides

2x = 18

2x/2 = 18/2 Divide both sides by 2

x = 9 shorter piece

The shorter piece would be 9 inches.

If you needed the longer piece too:

longer piece = x + 8

x + 8

= 9 + 8

= 17

The longer piece would be 17 inches.

Check your answer:

Longer + Shorter = 26 Substitute the lengths

17 + 9 = 26 Add

26 = 26 same number

LS = RS left side equals right side

The answer is correct.

3 0

3 years ago

Plz help me with this!!!!!!!!

LenaWriter [7]

Answer: √y

<u>Step-by-step explanation:</u>

$\sqrt[6]{y^3}=y^{\frac{3}{6}}=y^{\frac{1}{2}}=\boxed{\sqrt y}$

4 0

3 years ago

Use the factorization to find the values of x for which p(x) = 0. (x – 1)(x 1)(x 5) = 0 x – 1 = 0, so x = x 1 = 0, so x = x 5 =

Sladkaya [172]

Answer: (x – 1)(x + 1)(x + 5) = 0

x – 1 = 0, so x = 1

x + 1 = 0, so x = -1

x + 5 = 0, so x = -5

3 0

1 year ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

2 years ago