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3 years ago

Check answer please, will upvote!

Mathematics

1 answer:

Alexxandr [17]3 years ago

4 0

Hey there!

$\bold{y=4\bullet2x;x=-6}$

<em>If we found the value of " $\bold{x}$ " then plug it into the equation</em>
$\bold{y=4\times2(-6)}$
$\bold{2\times(-6)=-12}$
$\bold{4\times-12=-48}$
$\bold{-48=-48}$ $\checkmark$
$\boxed{\boxed{\bold{Answer:Yes}}}$

Good luck on your assignment and enjoy your day!

~ $\frak{LoveYourselfFirst:)}$

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Answer:

At 7% $54,000

At 9% $156,000

Step-by-step explanation:

Let x be the amount invested at 7%, Then 2x + 48000 will be the amount invested at 9%

We know that:

7% = 0.07 & 9% = 0.09

So we can write the interest equation as follows:

0.07x + 0.09 (2x + 48000) = 17820

0.07x + 0.18x + 4320 = 17820

0.25x + 4320 = 17820

Subtracting 4320 from both sides of the equation we get:

0.25x = 17820 - 4320

0.25x = 13500

Dividing both sides of the equation by 0.25 we get:

x = 13500 / 0.25

x = $54,000 invested at 7%

2 x 54000 + 48000

= $156,000 invested at 9%

Hence the amount invested at 7% is $54,000.

& the amount invested at 9% is $156,000.

5 0

4 years ago

There are 16 boys and 20 girls in a class. What part of the class is boys? What part girls?

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Answer:

girls 4/9 or (Decimal: 0.444444) percent is 44.4%

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3 years ago

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3 years ago

En la primera fase del proceso selectivo para Al cuerpo de profesores eliminan a cuatro novenos De los aspirantes mientras que e

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Answer:

The fraction of the applicants who have passed the two phases of the selection process is $\frac{10}{63}$ .

Step-by-step explanation:

The question is:

In the first phase of the selection process for the body of teachers they eliminate four-ninth of the applicants while in the second phase they eliminate 5/7 of those who passed the first phase. If there were 315 applicants what is the fraction of the applicants who have passed the two phases of the selection process?

The total number of applicants is

<em>N</em> = 315.

It is provided that 4/9th of the applicants were eliminated in the first phase.

Then the fraction of candidates who passed the first phase is:

Fraction who passed phase I = $1-\frac{4}{9}=\frac{5}{9}$

Now, it is also provided that 5/7 of those who passed the first phase were eliminated in the second phase.

Then the fraction of candidates who passed the second phase is:

Fraction who passed phase II = $1-\frac{5}{7}=\frac{2}{7}$

That is, 2/7 of the remaining applicants passed the second phase.

The fraction of the applicants who have passed the two phases is:

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Thus, the fraction of the applicants who have passed the two phases of the selection process is $\frac{10}{63}$ .

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3 years ago

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Answer:

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3 years ago