Hypotenuse = 22*sq root (2) I'm guessing you need to know the length of the triangle legs? The triangle leg of a 45 45 90 triangle = hypotenuse / sq root (2) triangle leg= 22* sq root (2) / sq root (2) triangle leg=22
Using the SOH CAH TOA method to solve the problem since the triangle is a 45°-45°-90° triangle which is a right angled triangle due to the presence of 90° as one or the angles.
If one of the sides is 22√2units,
Using SOH which states;
sin(theta) = Opposite/Hypotenuse
theta =45° (the angle facing one of the acute angle in the triangle)
Opposite side = 22√2
Substituting the datas into the formula we will have;