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Naddik [55]
3 years ago
7

What are three other expressions that are equivalent to 8x-12

Mathematics
1 answer:
Kisachek [45]3 years ago
3 0

Answer:

2(4x-6)

4(2x-3)

8(x-3/2)

Step-by-step explanation:

find all factors of 8 other than 1, you should have 3

divide the whole equation by the factor then multiply by the factor

2(8x-12)/2 = 2(4x-6)

4(2x-3)

8(x-3/2)

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Y=-3/8x-7 in standard form
Readme [11.4K]
Y = -3/8x - 7....add 3/8x from both sides
3/8x + y = -7 ...multiply both sides by 8
3x + 8y = - 56 <==
6 0
3 years ago
Given the functions below, find (f - g) (2).<br> f(x)<br> x2 + 3<br> g(x) = 4x – 3<br> =
kakasveta [241]

Answer:

(f - g)(2) = 2

Step-by-step explanation:

Given the functions below, find (f - g) (2).

f(x) = x² + 3

g(x) = 4x – 3

(f - g)(x) = (x²+3)-(4x-3)

(f - g)(x) = x²+3-4x+3

(f - g)(x) = x²-4x+6

(f - g)(2) = (2)²-4(2)+6

(f - g)(2) = 4-8+6

(f - g)(2) = 2

5 0
2 years ago
Suppose that Y1,....Yn are i.i.d random variables with a N (μγ, σ^2y) distribution. How would the probability density of Y chang
klemol [59]

Answer:

A

Step-by-step explanation:

As the sample size n increases, the sample mean (μy) becomes a more accurate estimate of the parametric mean, so the standard error of the mean becomes smaller. Therefore, the variance of y decreases and the distribution of y becomes highly concentrated around μy.

7 0
3 years ago
PLSSS HELP. WILL MARK BRAINLIEST. A rectangle has sides measuring (6x + 4) units and (2x + 11) units. Part A: What is the expres
Leni [432]

Answer:

Below.

Step-by-step explanation:

Part A: (6x+4)(2x+11)=12x^2+66x+8x+44=12x^2+74x+44

Part B: Degree = 2, Classification = Quadratic

Part C: The polynomial is closed because it is multiplied. You CANNOT close under division.

4 0
3 years ago
The perimeter of a playing field for a certain sport is 174 ft. The field is a rectangle, and the length is 45 ft longer than th
Leno4ka [110]

Answer:

21 ft by 66 ft

Step-by-step explanation:

From the question,

P = 2(L+W)............... Equation 1

Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.

If the Length of the Field is 45 ft longer than the width,

L = 45+W............ Equation 2

Substitute Equation 2 into equation 1

P = 2(45+W+W)

P = 90+4W............. Equation 3

Given: P = 174 ft.

Substitute into equation 3

174 = 90+4W

4W = 174-90

4W = 84

W = 84/4

W = 21 ft.

Substituting the value of W into equation 2

L = 45+21

L = 66 ft.

Hence the dimensions of the playing field is 21 ft by 66 ft

3 0
3 years ago
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