Question

8. If 0.795 moles of ammonia gas occupies 42.5 L at 670 torr, what is the Celsius temperature?

Answer 1

Answer: The temperature in degree Celsius is 301.31°C

Explanation:

To calculate the temperature, we use the equation given by ideal gas, which is:

$PV=nRT$

P = pressure of the gas = 670 torr = 0.882 atm   (Conversion factor: 1 atm = 760 torr)

V = volume of gas = 42.5 L

n = number of moles of gas = 0.795 mol

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of gas

Putting values in above equation, we get:

$0.882atm\times 42.5L=0.795mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times T\\\\T=574.31K$

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

$T(K)=T(^oC)+273$

$574.31=T(^oC)+273\\T(^oC)=301.31^oC$

Hence, the temperature in degree Celsius is 301.31°C