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sashaice [31]
3 years ago
9

How do the properties of the elements change as you move across a period on a periodic table from left to right?

Chemistry
1 answer:
Tomtit [17]3 years ago
8 0
B) The elements become less reactive.
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A. Use the words below to complete the sentences.
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Its Concentration, diffusion, a selectively Premable membrane, osmosis,diffusion, a selectively permeable membrane, osmosis, and diffusion
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Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
mamaluj [8]

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

2SO_2 + O_2 \to 2SO_3

The I.C.E table can be represented as:

                     2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,  

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction 2SO_2 + O_2 \to 2SO_3 = 0.8325;

If we want to find:

SO_2 + \dfrac{1}{2}O_2 \to SO_3

Then:

K_c = (0.8325)^{1/2}

\mathbf{K_c = 0.912}

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

7 0
3 years ago
What is the molarity of a solution in which 7.1 g of sodium sulfate is dissolved in enough water to make 100. mL of solution?
Sidana [21]

Answer:

0.50 M

Explanation:

Given data

  • Mass of sodium sulfate (solute): 7.1 g
  • Volume of solution: 100 mL

Step 1: Calculate the moles of the solute

The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

7.1g \times \frac{1mol}{142.02g} = 0.050mol

Step 2: Convert the volume of solution to liters

We will use the relation 1 L = 1000 mL.

100mL \times \frac{1L}{1000mL} =0.100L

Step 3: Calculate the molarity of the solution

M = \frac{moles\ of\ solute }{liters\ of\ solution} = \frac{0.050mol}{0.100L} =0.50 M

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What is the volume of the balloon when it rises in the atmosphere to a place where pressure is 640mmHg

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