Answer:
Hello
12 grams
The mass of one mole of carbon-12 atoms is 12 grams.
Hope it helps You.....
Explanation:
Given the percentage composition of HC as C → 81.82 % and H → 18.18 %
So the ratio of number if atoms of C and H in its molecule can will be:
C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8
So the Empirical Formula of hydrocarbon is:
C 3 H 8
As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol
Now let Molecular formula of the HC be ( C 3 H 8 ) n
Using molar mass of C and H the molar mass of the HC from its molecular formula is:
( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1
Hence the molecular formula of HC is C 3 H 8
Does that help?
Ionic compounds are formed by the complete transfer of electrons from more electronegative elements to less electronegative elements.
7. <u>Sodium Nitride (Na₃N)</u> is an ionic substance.
8. The ionic formula for <u>Lithium Oxide is Li₂O</u>
9. The <u>compound SrF₂</u>
10. Aluminum Sulfide is a chemical compound with the <u>formula Al₂S₃.</u>
An ionic compound is a chemical compound composed of ions held together via electrostatic forces termed ionic bonding. The compound is neutral standard but includes definitely charged ions known as cations and negatively charged ions known as anions.
An ionic compound is a chemical compound composed of ions held collectively by means of electrostatic forces termed ionic bonding. The compound is neutral normal however consists of positively charged ions known as cations and negatively charged ions referred to as anions. Ionic compounds incorporate ions and are held collectively via the attractive forces of most of the oppositely charged ions.
Learn more about ionic compounds here:-
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<u>Answer:</u> The theoretical yield of the lithium chlorate is 1054.67 grams
<u>Explanation:</u>
To calculate the mass for given number of moles, we use the equation:
Actual moles of lithium chlorate = 9.45 moles
Molar mass of lithium chlorate = 90.4 g/mol
Putting values in above equation, we get:
To calculate the theoretical yield of lithium chlorate, we use the equation:
Actual yield of lithium chlorate = 854.28 g
Percentage yield of lithium chlorate = 81.0 %
Putting values in above equation, we get:
Hence, the theoretical yield of the lithium chlorate is 1054.67 grams
There are two ways to solve this problem. We can use the ICE method which is tedious and lengthy or use the Henderson–Hasselbalch equation. This equation relates pH and the concentration of the ions in the solution. It is expressed as
pH = pKa + log [A]/[HA]
where pKa = - log [Ka]
[A] is the concentration of the conjugate base
[HA] is the concentration of the acid
Given:
Ka = 1.8x10^-5
NaOH added = 0.015 mol
HC2H3O2 = 0.1 mol
NaC2H3O2 = 0.1 mol
Solution:
pKa = - log ( 1.8x10^-5) = 4.74
[A] = 0.015 mol + 0.100 mol = .115 moles
[HA] = .1 - 0.015 = 0.085 moles
pH = 4.74 + log (.115/0.085)
pH = 4.87
