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4 years ago

Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?

Mathematics

2 answers:

Darina [25.2K]4 years ago

7 0

Answer:

She has 6 quarters.

saul85 [17]4 years ago

5 0

Answer:

<em>3n; 2 nickels and 6 quarters</em>

Step-by-step explanation:

"Peggy had three times as many quarters as nickels."

Whatever number of nickels she has, the number of quarters is 3 times as many.

Since she has n nickels, she has 3 times n quarters.

The number of quarters is 3n.

A nickel is worth $0.05, so n nickels are worth 0.05n.

A quarter is worth $0.25, so 3n quarters are worth 0.25(3n).

0.05n + 0.25(3n) = 1.60

0.05n + 0.75n = 1.6

0.8n = 1.6

n = 2

She has 2 nickels.

3n = 3(2) = 6

She has 6 quarters.

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Read 2 more answers

A bank contains 35 coins, all nickels and quarters. The total value of coins is $8.15. How many of each coin does the bank conta

Lina20 [59]

n + q = 35

n = 35-q

0.05n + 0.25q = 8.15

0.05(35-q) +0.25q = 8.15

1.75 -0.05q + 0.25q =8.15

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4 years ago

What is slope intercept form of -6+3y=-3x

shutvik [7]

Esay, first what you have to do us move -6 to the right side and now you will have 3y=-3x+6, what you want to do next is to divide 3y by both sides and your final answer is y=-x+2, hope this helps.

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3 years ago

Help! Please! Geometry!!

DiKsa [7]

By the Segment Addition Postulate, SAP, we have

XY + YZ = XZ

YZ = XZ - XY = 5 cm - 2 cm = 3 cm

10.

M is the midpoint of XZ=5 cm so

XM = 5 cm / 2 = 2.5 cm

11.

XY + YM = XM

YM = XM - XY = 2.5 cm - 2 cm = 0.5 cm

12.

The midpoint is just the average of the coordinate A(-3,2), B(5,-4)

$M = (A+B)/2 = \left( \dfrac{-3 + 5}{2}, \dfrac{2 + -4}{2} \right)$

Answer: M is (1,-1)

You'll have to plot it yourself.

13.

For distances we calculate hypotenuses of a right triangle using the distnace formula or the Pythagorean Theorem.

$AB^2 =(5 - -3)^2 + (-4 - 2)^2 = 8^2 + 6^2 = 100$

Answer: AB=10

M is the midpoint of AB so

Answer: AM=MB=5

14.

B is the midpoint of AC. We have A(-3,2), B(5,-4)

B = (A+C)/2

2B = A + C

C = 2B - A

C = ( 2(5) - -3, 2(-4) - 2 ) = (13, -10)

Check the midpoint of AC:

(A+C)/2 = ( (-3 + 13)/2, (2 + -10)/2 ) = (5, -4) = B, good

Answer: C is (13, -10)

Again I'll leave the plotting to you.

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3 years ago