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3 years ago

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A dressmaker needs to cut 18-inch pieces of ribbon from rolls of ribbon that are 3 feet in length. How many 18-inch pieces can t

he dressmaker cut from 15 of these rolls of ribbon?

2 answers:

lora16 [44]3 years ago

8 0

Answer

18+3=21

21-18=3

i think 3

Bezzdna [24]3 years ago

3 0

Answer:

1. how many inches in total? if each roll is 3 feet in length and considering that there are 12 inches per foot, she has <u>36 inches of ribbon initially.</u>

(if the question is asking about how many inches she has in the 15 rolls, she would have 45 feet in length which would amount to 540 inches.)

2. How many from 15? In 15 rolls of ribbon, there would be a total of 540 inches of ribbon, so by dividing that by 18 inches (the size of each cut) <u>she will be able to cut out exactly 30 pieces.</u>

<u></u>

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What is equity and liquidity?<br> (This subject is personal financing but I couldn't find it.)

Naily [24]

Liquidity describes the degree to which an asset or security can be quickly bought or sold in the market without effecting the assets prices, while equity is the value of the shares issued by a company.

8 0

3 years ago

I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

(a) Find the common difference of an A.P. whose first term is 5 and the number of terms is 30 and sum 1455.

Alexxandr [17]

Sum = n/2[2a + (n - 1)d] where a = first term, n = number of terms and d = common difference

(a) 30/2(2 x 5 + (30 - 1) x d) = 1455
10 + 29d = 1455 / 15
29d = 97 - 10
d = 87 / 29 = 3

(b) 7/2(2 x 9 + (7 - 1)d) = 0
18 + 6d = 0
6d = -18
d = -3

4 0

3 years ago

12.5% of what number 24?

Valentin [98]

Answer:

192

Step-by-step explanation:

12.5% is 24.

So 100% will be (100/12.5) x 24 = 192.

Done.

6 0

2 years ago

Read 2 more answers

Https://learning.k12.com/content/enforced/361756-COF_ID92747/Extended%20Answer%202.GIF?_&d2lSessionVal=6bj13oL4Dap6gjQyXIPmV

777dan777 [17]

Post a pic for me so i can answer

4 0

3 years ago