Answer:
Mean, E(x) = 0.17
Variance, V(x) = 0.12
Step-by-step explanation:
90% contains no defective bulbs, P(X=0) = 0.9
5% contain one defective bulbs, P(X=1) = 0.05
3% contain two defective bulbs, P(X=2) = 0.03
2% contain three defective bulbs, P(X=3) = 0.02
The mean for the number of defective bulbs:
Variance for the defective bulbs:
V(x) = 0.29 - 0.17
V(x) = 0.12