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stepladder [879]
2 years ago
11

MAJOR HELP!! Please help someone please..

Mathematics
1 answer:
VMariaS [17]2 years ago
7 0

Answer:

x=8.48

Step-by-step explanation:

Sin 45 = x/12

x=12 x sin 45

x=12 x .7071

x=8.48

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Which fractions add together to make 5/8<br> 5<br> ​
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\frac{10}{16}

Step-by-step explanation:

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Suppose a certain capsule is manufactured so that the dosage of the active ingredient follows the distribution Y ~ N(μ = 10 mg,
lianna [129]

Answer:

(a) Probability that Y falls into the dangerous region is 0.0013.

(b) Probability that the mean Y-bar falls into the dangerous region is 0.00001.

Step-by-step explanation:

We are given that a certain capsule is manufactured so that the dosage of the active ingredient follows the distribution Y ~ N(μ = 10 mg, σ = 1 mg).

A dosage of 13 mg is considered dangerous.

Let Y = <u><em>dosage of the active ingredient </em></u>

The z-score probability distribution for normal distribution is given by;

                                 Z  =  \frac{ Y-\mu}{\sigma} } }  ~ N(0,1)

where, \mu = population mean = 10 mg

            \sigma = standard deviation = 1 mg

(a) Probability that Y falls into the dangerous region is given by = P(Y \geq 13 mg)

       P(Y \geq 13 mg) = P( \frac{ Y-\mu}{\sigma} } } \geq \frac{ 13-10}{1} } } ) = P(Z \geq 3) = 1 - P(Z < 3)  

                                                          = 1 - 0.9987 = <u>0.0013</u>

The above probability is calculated by looking at the value of x = 3 in the z table which has an area of 0.9987.

(b) We are given that a dosage of 13 mg is considered dangerous. And we sample 49 capsules at random.

Let \bar Y = sample mean dosage

The z-score probability distribution for sample mean is given by;

                                 Z  =  \frac{\bar Y-\mu}{\frac{\sigma}{\sqrt{n} } } } }  ~ N(0,1)

where, \mu = population mean = 10 mg

            \sigma = standard deviation = 1 mg

            n = sample of capsules = 49

So, Probability that the mean Y-bar falls into the dangerous region is given by = P(\bar Y \geq 13 mg)

          P(Y \geq 13 mg) = P( \frac{\bar Y-\mu}{\frac{\sigma}{\sqrt{n} } } } } \geq \frac{13-10}{\frac{1}{\sqrt{49} } } } } ) = P(Z \geq 21) = 1 - P(Z < 21)  

                                                             = <u>0.00001</u>

6 0
3 years ago
What percent of 900 is 18
horsena [70]

Fastest method for calculating what percent of 900 is 18

Assume the unknown value is 'Y', and 18 of 900 can be written as:

Y =  

18

900

By multiplying both numerator and denominator by 100 we will get:

Y =  

18

900

x  

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100

=  

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Y = 2%

Answer: 2 percent of 900 is 18

If you want to use a calculator, simply enter 18÷900x100 and you will get your answer which is 2

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