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3 years ago

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Which of the following is not a major principle of experimentation?

2 answers:

Anestetic [448]3 years ago

7 0

Hey there,

Based on my research, the experimentation of the of which is NOT the major principle of the experimentation would be <span>Segmentation.

Hope this helps.
~Jurgen</span>

Lina20 [59]3 years ago

7 0

Hello

Your answer will be B.

Hoped This Helped!

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Three friends got jobs at stores in the mall. Nina earns $117.60 for hours 14 of work. Ty earns for $148.50 hours 18 of work. Ki

marysya [2.9K]

Answer:

Kim has the highest pay rate in dollars per hour

Step-by-step explanation:

we know that

To find out the unit pay rate divide the total earning by the total time

so

Nina earns $117.60 for hours 14 of work

$\frac{117.60}{14}=\$8.4\ per\ hour$

Ty earns for $148.50 hours 18 of work

$\frac{148.50}{18}=\$8.25\ per\ hour$

Kim earns for $137.60 hours 16 of work

$\frac{137.60}{16}=\$8.60\ per\ hour$

$8.6 > 8.4 > 8.25$

therefore

Kim has the highest pay rate in dollars per hour

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3 years ago

Make v the subject of the relation KE = ½mv²

Irina18 [472]

Answer:

$v=\sqrt{\frac{2KE}{m} }$

Step-by-step explanation:

$KE = 1/2mv^2$

$KE/1/2=mv^2$

$2KE=mv^2$

$2KE/m=v^2$

$\sqrt{2KE/m} =v$

7 0

3 years ago

Read 2 more answers

The diagonal of a side of rhombus are of equal length. Find the measures of angles of the rhombus.

sergij07 [2.7K]

<u>Explanation</u><u>:</u>

Consider ABCD is a rhombus

We know that

All sides are equal in rhombus i.e,

⇛AB=BC=CD=DA

and AC and BD are digonals

Given that

Diagonal and the side of the rhombus are equal.

⇛AB = BC = CD = DA = AC

Diagonal AC divides the rhombus into two triangles .

They are ∆ BAC and ∆ DAC

In triangle BAC

BA=BC=AC,(Given)

⇛∠ BAC=∠ABC= ∠ACB =60°→→→Eqn(i)

Similarly in ∆DAC ,

DA=DC=AC

⇛∠DAC=∠ACD=∠ADC=60°→→→Eqn(ii)

From eqn(i) and eqn(ii)

∠A=∠BAC+∠DAC=60°+60°=120°

and

∠B= ∠ABC = 60°.

and

∠C=∠ACB+∠ACD=60°+60°=120°

and

∠D =∠ADC=60°

∴ ∠A = 120° , ∠B = 60° ,∠C = 120° & ∠D = 60°

<u>Answer:</u><u>-</u>The measures of the all angles in the rhombus are 120° , 60° ,120° and 60°.

Note: [Figure refers in the attached file.

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2 years ago

V1 - 2 sin cos 0 = cos 0 - sin

kramer

$\sqrt{1 - 2sin θ \cosθ } = \sqrt{ {sin}^{2} θ + {cos}^{2}θ - 2 sinθcosθ } = \sqrt{ {(cosθ - sinθ) }^{2} } = cosθ - sinθ$

4 0

2 years ago

Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

6 0

2 years ago