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3 years ago

Which of the following is not a major principle of experimentation?

2 answers:

7 0

Hey there,

Based on my research, the experimentation of the of which is NOT the major principle of the experimentation would be <span>Segmentation.

Hope this helps.
~Jurgen</span>

Lina20 [59]3 years ago

7 0

Hello

Your answer will be B.

Hoped This Helped!

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If the simple interest on $5,000 for 9 years is $1,800, then what is the interest rate?

Law Incorporation [45]

$I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$1800\\ P=\textit{original amount deposited}\dotfill & \$5000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &9 \end{cases} \\\\\\ 1800=5000(\frac{r}{100})(9)\implies \cfrac{1800}{5000(9)}=\cfrac{r}{100}\implies \cfrac{1}{25}=\cfrac{r}{100} \\\\\\ 100=25r\implies \cfrac{100}{25}=r\implies \stackrel{\%}{4}=r$

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2 years ago

Solve 4x − 2(x + 1) = 3x + 10. (5 points)

Dmitry [639]

Answer:

x=-12

Step-by-step explanation:

4x-2x-2=3x+10

2x-2=3x+10

+2 =3x+12

2x=3x+12

-3x=12

-x=12

x=-12

4 0

2 years ago

The nth term of a sequence is represented by 3n4−10/6n4+7 . What is the limit of the the nth term as n becomes increasingly larg

Cerrena [4.2K]

Answer:

Step-by-step explanation:

Given the limit of the function expressed as;

$\lim_{n \to \infty} \frac{3n^4-10}{6n^4+7} \\$

To take the limit, we nee to divide through by the highest power of n first

$\lim_{n \to \infty} \frac{3n^4/n^4-10/n^2}{6n^4/n^4+7/n^4}\\= \lim_{n \to \infty} \frac{3-10/n^2}{6+7/n^4}\\= \frac{3-10/(\infty)^2}{6+7/(\infty)^4}\\= \frac{3-0}{6-0}\\= \frac{3}{6}\\ = \frac{1}{2}\\$

Hence the limit of the the nth term as n becomes increasingly large is 1/2

3 0

3 years ago

= Solving a word problem with two unknowns using a linear... A washer and a dryer cost $650 combined. The washer costs $100 less

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Answer:

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2 years ago

Solve y=x+5 and 2x-3y=4

stepan [7]

Answer:

x= -19

y= -14

Step-by-step explanation:

Substitution.

It tells you what y is already. You substitute that into the second equation and then solve. Then you use that answer and substitute it back into the first equation's x, and then you'll get your full answer.

Hope this helps <3

4 0

1 year ago

Read 2 more answers