Ella is 13 years, four months, and 19 days old.
8y-6( add the variables together then add 8 to negative 14
Answer:
is c
Step-by-step explanation:
Answer:
lim (x, y, z) → (0, 0, 0) [x*y*z]/(x^2+y^2+z^2)=0
Step-by-step explanation:
First, we need to put the spherical coordinates equations that we will use in our problem
x = p*sin∅cos Ф
y = p*sin∅sinФ
z=p*cos∅
Then we will state the problem
lim (x, y, z) → (0, 0, 0) [x*y*z]/(x^2+y^2+z^2)
Using the spherical coordinates we get
(x^2+y^2+z^2) = p^2
Which will make our limit be
lim p→0+ [p*sin∅cos Ф*p*sin∅sinФ
*p*cos∅]/(x^2+y^2+z^2)
after solving limit:
lim (x, y, z) → (0, 0, 0) [x*y*z]/(x^2+y^2+z^2)=0
It's not obvious here, but you're being asked to find a linear equation for the velocity of the car, given two points on the line that represents this velocity.
Find the slope of the line segment that connects the points (3 hr, 51 km/hr) and (5 hr, 59 km/hr). Graph this line. Where does this line intersect the y-axis? Find the y-value; it's your "y-intercept," b.
Now write the equation: velocity = (slope of line)*t + b
The units of measurement of "slope of line" must be "km per hour squared," and those of the "y-intercept" must be "km per hour."
Part B: Start with the y-intercept (calculated above). Plot it on the vertical axis of your graph. Now label the horizontal axis in hours: {0, 1, 2, 3, 4, 5, 6}. Draw a vertical line through t=6 hours. It will intercept both the horiz. axis and the sloping line representing the velocity as a function of time. Show only the part of the graph that extends from t=0 hours to t=6 hours.
