First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
----------------------
4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2
Answer:
<h2>Neither Gustavo nor Yuki</h2>
Step-by-step explanation:
It's an arithmetic sequence.
The difference is constant.
The explicit formula of an arithmetic sequence:
Substitute:
<em>use distributive property</em>
Answer:
9 minutes
Step-by-step explanation:
60=15+5t
45=5t : subtract 15 from both sides
9=t : divide by 5 for both side
Yes, you can use division to solve a missing factor problem
Answer:
a little bit of a very nice and smart and k liye kuch bhi nahi ha ha bol rahe hai
