No' of molecules divide by avogadro number , 6×6.023×10^23 so (2.2×10^22)÷(6.023×10^23)
= 0.03653 moles
moles × Molar mass = mass
n×Mr=m
0.03653×40 = 1.46 grams
If I were you, I'd try to go with this one :
![[(6)(-241.8)+(5)(-393.5)]-[-35.1] =-481.6](https://tex.z-dn.net/?f=%20%5B%286%29%28-241.8%29%2B%285%29%28-393.5%29%5D-%5B-35.1%5D%20%3D-481.6)
. I think that is a solution you have to find. Just use the sum of standard enthalpies of products and <span>of reactants. Hope you will find it helpful!</span>
Alpha partical is a He nucleus. When decaying alpha particle mass is reduced by 4 and atomic number is reduced by 2.
The actual element which has 102 protons is No (Nobelium).
Since it has 167 neutrons, the mass = protons + neutrons = 102 + 167 = 269
after an alpha decay, the new element formed has 100 protons which is Fm ( Fermium)
the alpha decaying equation is,
₁₀₂²⁶⁹No → ₁₀₀²⁶⁵Fm + ₂⁴α + heat
the total mass and the atomic number( numbe rof protons) must be equal in both sides.
Answer:
K = 8.6x10⁻⁶
Explanation:
<em>a chemist finds that a 5.2L reaction vessel...</em>
To solve this question we need first to find the equation of the equilibrium constant using the chemical eqiation:
TiCl₄(l) ⇄ Ti(s) + 2Cl₂(g)
The equilibrium constant expression is:
K = [Cl₂]²
<em>Because equilibrium constant is defined as the ratio berween concentrationa of products over reactant powered to its reaction coefficient. But pure liquids as TiCl₄(l) and pure solids as Ti(s) are not taken into account</em>
<em />
Now, we need to find the molar concentration of Cl₂, [Cl₂]:
<em>Moles Cl₂ -Molar mass: 70.9g/mol-:</em>
1.08g * (1mol / 70.9g) = 0.0152 moles / 5.2L =
2.93x10⁻³M = [Cl₂]
K = (2.93x10⁻³)²
<h3>K = 8.6x10⁻⁶</h3>
