Calculate the rms speed of an oxygen gas molecule, o2, at 17.0 ∘c .
2 answers:
The μ rms speed = <u>475,433 m / s </u>
<h3> Further explanation </h3>Gas particles move randomly (both speed and direction, as vector)
Average velocities of gases can be expressed as root-mean-square velocity. (μ rms)
R = gas constant, 8,314 J / mol K
T = temperature, K
Mm = molar mass of the gas particles , Kg
μ rms = root mean square velocity of Gas Particles.,m/s
From this equation shows that the velocity of the gas is inversely proportional to the molar mass of the gas particles
μ ≅ 1 / Mm
So that the greater the molar mass of the gas particles, the smaller the speed (the slowest)
Oxygen gas molecule, O₂ has a molar mass: 0.032 kg / mol
T = 17 °C = 17 + 273 = 290 K
then:
<h3> Learn more </h3>
kinetic molecular theory
The gas particle that travels the slowest
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remember that when you put two atoms together, you "cross" the charges and put them as a suffix. I have attached a picture as a visual aid of how to do this.
so, if you put together Fe+2 and oxygen you can get Fe2O2, which simplifies to FeO since the have the same suffix.this compound is called Iron (II) oxide because the iron is the one with charge +2.
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