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3 years ago

Why alcohol is completely miscrible with water. explain?

Chemistry

1 answer:

Julli [10]3 years ago

7 0

Answer:

Both water and ethanol are polar and due to miscibility, Ethanol has OH groups capable of forming hydrogen bonds with the water molecule. Hydrogen bonds are formed when the oxygen attached to the alcohols form hydrogen bonds between the molecules and water. This explains the solubility of methanol.

Explanation:

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When a counterfeit detection pen is used on an authentic bill, what color does it turn?

NeX [460]

Answer:

Explanation:

the answer is C, sometimes it can be brown

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4 years ago

How do you write 145,000,000 in scientific notation?

belka [17]

Answer:

$\boxed{1.45 \times 10^{8}}$

Explanation:

A number in scientific notation has the form N × 10ⁿ

where N is a decimal number called the mantissa and n is an integer called the exponent.

We must have 1 ≤ N < 10

Step 1. Determine the mantissa

Move the decimal place to the left to create a new number between 1 and 10.

145 000 000 ⟶ 1.450 000 00; N = 1.45

Step 2. Determine the exponent.

The exponent is the number of times you moved the decimal to get the mantissa.

You moved the decimal eight places to the left, so the exponent n = 8.

Step 3. Write the number in scientific notation

The number in scientific notation is $\boxed{1.45 \times 10^{8}}$ .

5 0

3 years ago

Which of the following aqueous solutions are good buffer systems? . 0.32 M calcium chloride + 0.27 M sodium chloride 0.35 M ammo

irga5000 [103]

Answer:

0.12 M hydrofluoric acid + 0.17 M potassium fluoride

Explanation:

To make a buffer, you must to have an aqueous mixture of a weak acid and its conjugate base or vice versa.

Knowing that:

0.32 M calcium chloride + 0.27 M sodium chloride: is not a good buffer system because CaCl₂ and NaCl are both salts.

0.35 M ammonia + 0.36 M calcium hydroxide is not a good buffer system because ammonia is a weak base but calcium hydroxide is a strong base

0.19 M barium hydroxide + 0.28 M barium chloride is not a good buffer system because Ba(OH)₂ is a strong base.

0.12 M hydrofluoric acid + 0.17 M potassium fluoride is a good buffer system because HF is a weak acid and KF (F⁻ in aqueous medium), is its conjugate base

0.20 M hydrobromic acid + 0.22 M sodium bromide is not a good buffer system because HBr is a strong acid.

7 0

3 years ago

Hurry I need the answer asap

kifflom [539]

Answer:

its solid

Explanation:

hope it helps u

3 0

3 years ago

When 1.2383 g of an organic iron compound containing Fe, C, H, and O was burned in O2, 2.3162 g of CO2 and 0.66285 g of H2O were

uysha [10]

Answer:

$\boxed{\text{C$_{15}$H$_{21}$FeO$_{6}$}}$

Explanation:

Let's call the unknown compound X.

1. Calculate the mass of each element in 1.23383 g of X.

(a) Mass of C

$\text{Mass of C} = \text{2.3162 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.632 07 g C}$

(b) Mass of H

$\text{Mass of H} = \text{0.66285 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.074 157 g H}$

(c)Mass of Fe

(i)In 0.4131g of X

$\text{Mass of Fe} = \text{0.093 33 g Fe$_{2}$O$_{3}$}\times \dfrac{\text{111.69 g Fe}}{\text{159.69 g g Fe$_{2}$O$_{3}$}} = \text{0.065 277 g Fe}$

(ii) In 1.2383 g of X

$\text{Mass of Fe} = \text{0.065277 g Fe}\times \dfrac{1.2383}{0.4131} = \text{0.195 67 g Fe}$

(d)Mass of O

Mass of O = 1.2383 - 0.632 07 - 0.074 157 - 0.195 67 = 0.336 40 g

2. Calculate the moles of each element

$\text{Moles of C = 0.63207 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.052 629 mol C}\\\\\text{Moles of H = 0.074157 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.073 568 mol H}\\\\\text{Moles of Fe = 0.195 67 g Fe} \times \dfrac{\text{1 mol Fe}}{\text{55.845 g Fe}} = \text{0.003 5038 mol Fe}\\\\\text{Moles of O = 0.336 40} \times \dfrac{\text{1 mol O}}{\text{16.00 g O}} = \text{0.021 025 mol O}$

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

$\text{C: } \dfrac{0.052629}{0.003 5038}= 15.021\\\\\text{H: } \dfrac{0.073568}{0.003 5038} = 20.997\\\\\text{Fe: } \dfrac{0.003 5038}{0.003 5038} = 1\\\\\text{O: } \dfrac{0.021025}{0.003 5038} = 6.0006$

4. Round the ratios to the nearest integer

C:H:O:Fe = 15:21:1:6

5. Write the empirical formula

$\text{The empirical formula is } \boxed{\textbf{C$_{15}$H$_{21}$FeO$_{6}$}}$

5 0

3 years ago

Why alcohol is completely miscrible with water. explain?​

Why alcohol is completely miscrible with water. explain?