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3 years ago

Does the mass of the sealed jar and its contents change upon the vaporization of the liquid?

1 answer:

4 0

The answer is No. That is the mass of the sealed jar and its contents does not change upon the vaporization of the liquid, as according to the “law of conservation of mass” , the mass remain conserved when no matter is escape, the mass will remain constant and here also as the jar is sealed, no matter is escaped thus no mass change will be there.

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At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 L . What volume wo

Nostrana [21]

Taking into account the Charles's law, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.

<h3>Charles's Law</h3>

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, at a constant pressure.

Volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles's law is a law that says that the quotient that exists between the volume and the temperature will always have the same value:

V÷ T= k

Considering an initial state 1 and a final state 2, it is satisfied:

V1÷ T1= V2÷ T2

<h3>Volume at 65°C</h3>

In this case, you know:

V1= 22.4 L
T1= 0 C= 273 K
V2= ?
T2= 65 C= 338 K

Replacing in Charles's law:

22.4 L÷ 273 K= V2÷ 338 K

Solving:

(22.4 L÷ 273 K) ×338 K= V2

Finally, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.

Learn more about Charles's law:

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3 0

1 year ago

What type of bond is present in the Cl2 molecule?

Maksim231197 [3]

Answer: single covalent bond

Explanation: Chlorine is a simple molecule. each chlorine atom can count 8 electrons in its outer shell. with other chlorine atoms. One pair of shared electrons form a single covalent bond.

3 0

3 years ago

Read 2 more answers

How could you separate a mixture of acetone and a-naph<br>thol

Ganezh [65]

You could use distillation.

Hope this helps

7 0

4 years ago

How many moles of the Htion in 395 mL of 1.325 M sulfuric acid (H2SO4).

Irina18 [472]

Answer:

1.05 mol

Explanation:

Step 1: Given data

Molarity of sulfuric acid (M): 1.325 M (1.325 mol/L)

Volume of solution (V): 395 mL (0.395 L)

Step 2: Calculate the moles of sulfuric acid (n)

We will use the following expression.

M = n/V

n = M × V

n = 1.325 mol/L × 0.395 L = 0.523 mol

Step 3: Calculate the moles of H⁺

H₂SO₄ dissociates completely according to the following equation.

H₂SO₄ ⇒ 2 H⁺ + SO₄²⁻

The molar ratio of H₂SO₄ to H⁺ is 1:2. The moles of H⁺ are 2/1 × 0.523 mol = 1.05 mol.

7 0

2 years ago

What volume of benzene (C6H6, d= 0.88 g/mL, molar mass = 78.11 g/mol) is required to produce 1.5 x 103 kJ of heat according to t

Anton [14]

Answer:

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

Explanation:

<u>Step 1:</u> Data given

Density of benzene = 0.88 g/mL

Molar mass of benzene = 78.11 g/mol

Heat produced = 1.5 * 10³ kJ

<u>Step 2:</u> The balanced equation

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔH°rxn = -6278 kJ

<u>Step 3:</u> Calculate moles of benzen

1.5 * 10³ kJ * (2 mol C6H6 / 6278 kJ) = 0.478 mol C6H6

<u>Step 4:</u> Calculate mass of benzene

Mass benzene : moles benzene * molar mass benzene

Mass benzene= 0.478 * 78.11 g

Mass of benzene = 37.34 grams

<u>Step 5:</u> Calculate volume of benzene

Volume benzene = mass / density

Volume benzene = 37.34 grams / 0.88g/mL

Volume benzene = 42.4 mL

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

4 0

3 years ago