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4 years ago

What is 1+1/2+2/3? Correct answer needed for a quiz.

Mathematics

2 answers:

aleksklad [387]4 years ago

8 0

Answer:

13/6

Step-by-step explanation:

1+0.5=1.5=9/6

9/6+4/6=13/6

padilas [110]4 years ago

3 0

The answer is 1 because if you add 1 to 1 that Would be 2 then you divide 2 to 2 then it’s 1 then you add 2 and get 3 then you divide 3 and that would equal 1 so your final answer will be 1

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Can someone check whether its correct or no? this is supposed to be the steps in integration by parts

Gwar [14]

Answer:

$\displaystyle - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}$

Step-by-step explanation:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

Given integral:

$\displaystyle -\int \dfrac{\sin(2x)}{e^{2x}}\:\text{d}x$

$\textsf{Rewrite }\dfrac{1}{e^{2x}} \textsf{ as }e^{-2x} \textsf{ and bring the negative inside the integral}:$

$\implies \displaystyle \int -e^{-2x}\sin(2x)\:\text{d}x$

Using <u>integration by parts</u>:

$\textsf{Let }\:u=\sin (2x) \implies \dfrac{\text{d}u}{\text{d}x}=2 \cos (2x)$

$\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}$

Therefore:

$\begin{aligned}\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\sin (2x)- \int \dfrac{1}{2}e^{-2x} \cdot 2 \cos (2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\sin (2x)- \int e^{-2x} \cos (2x)\:\text{d}x\end{aligned}$

$\displaystyle \textsf{For }\:-\int e^{-2x} \cos (2x)\:\text{d}x \quad \textsf{integrate by parts}:$

$\textsf{Let }\:u=\cos(2x) \implies \dfrac{\text{d}u}{\text{d}x}=-2 \sin(2x)$

$\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}$

$\begin{aligned}\implies \displaystyle -\int e^{-2x}\cos(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\cos(2x)- \int \dfrac{1}{2}e^{-2x} \cdot -2 \sin(2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x\end{aligned}$

Therefore:

$\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x$

$\textsf{Subtract }\: \displaystyle \int e^{-2x}\sin(2x)\:\text{d}x \quad \textsf{from both sides and add the constant C}:$

$\implies \displaystyle -2\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+\text{C}$

Divide both sides by 2:

$\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{4}e^{-2x}\sin (2x) +\dfrac{1}{4}e^{-2x}\cos(2x)+\text{C}$

Rewrite in the same format as the given integral:

$\displaystyle \implies - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}$

5 0

2 years ago

Justin is saving money for a new gaming console. He currently has $200 in a saving account and each week $10 to his balance. In

Nikitich [7]

$500 - $200 = $300 dollars left.

$300 divided by $10 = 30 weeks.

8 0

4 years ago

Please help me with this.

Scorpion4ik [409]

Answer:

Step-by-step explanation:

7 0

3 years ago

A movie theater has been charging $10.00 per person and selling about 500 tickets on a typical weeknight. After surveying their

kifflom [539]

Answer:

$p(x) = -0.01x + 15$

Step-by-step explanation:

Given

Let x represent the number of tickets, and p the charges

$(x_1,p_1) = (500,10)$

A reduction of 50c gives an increment of 50 tickets.

This gives:

$(x_2,p_2) = (500+50,10-0,5)$ ---- $50c = \$0.5$

$(x_2,p_2) = (550,9.5)$

Required

Determine the demand function

First, calculate the slope:

$m = \frac{p_2 - p_1}{x_2 - x_1}$

$m = \frac{9.5 - 10}{550-500}$

$m = \frac{-0.5}{50}$

$m = -0.01$

So, the equation is:

$p = m(x - x_1) + y_1$

$p = -0.01(x - 500) +10$

$p = -0.01x + 5 +10$

$p = -0.01x + 15$

Hence, the function is:

$p(x) = -0.01x + 15$

4 0

3 years ago

Dairy farmers are aware there is often a linear relationship between the age, in years, of a dairy cow and the amount of milk pr

Jobisdone [24]

Answer:

B. A cow of 5 years is predicted to produce 5.5 more gallons per week.

Step-by-step explanation:

Let $M(a) = 40.8-1.1\cdot a$ , where $a$ is the age of the dairy cow, measured in years, and $M(a)$ is the predicted milk production, measured in gallons per week.

Besides, we consider $a_{1}$ and $a_{2}$ , such that $a_{1}\ne a_{2}$ , we define the difference between predicted milk productions ( $\Delta M$ ) below: