Simplify l3r-15l if r<5 SOLVE NOW PLEASE

Mathematics

2 answers:

rusak2 [61]3 years ago

7 0

Answer:

Step-by-step explanation:

katrin [286]3 years ago

5 0

Answer:

-3r + 15 ---> answer

Step-by-step explanation:

r < 5

You are going to multiply both sides with 3. The reason being is that 3 is a positive number and the equality sign will not change if you use +3.

3r < 15

Now, subtract 15 from both sides, you will get this:

3r < 15

-15 -15

-------------

3r — 15 < 0

Lastly, using the Modulus function, we are going to add a negative sign to the content of our previous step because it's already negative.

So, -3r + 15 is the final solution if r < 5 in the given equation of l3r-15l

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If a₁ = 4 and an = 5an-1 then find the value of a5.

igor_vitrenko [27]

The value of $a_{5}$ is 2500, when $a_{1}=4$ and $5a_{n-1}$ .

Given that, $a_{1}=4$ and $5a_{n-1}$ .

We need to find the value of $a_{5}$ .

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An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Now, to find the value of $a_{5}$ :

$a_{2} =5a_{2-1}=5a_{1}=5 \times4=20$