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Irina-Kira [14]
3 years ago
11

Simplify l3r-15l if r<5 SOLVE NOW PLEASE

Mathematics
2 answers:
rusak2 [61]3 years ago
7 0

Answer:

Step-by-step explanation:

3

katrin [286]3 years ago
5 0

Answer:

-3r + 15 ---> answer

Step-by-step explanation:

r < 5

You are going to multiply both sides with 3. The reason being is that 3 is a positive number and the equality sign will not change if you use +3.

3r < 15

Now, subtract 15 from both sides, you will get this:

3r < 15

-15   -15

-------------

3r — 15 < 0

Lastly, using the Modulus function, we are going to add a negative sign to the content of our previous step because it's already negative.

So, -3r + 15 is the final solution if r < 5 in the given equation of l3r-15l

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the area of the triangle below is 1/4 square meters. what is the length of the base. express your answer in simplest form
Alexeev081 [22]

Answer:

4/5

Step-by-step explanation:

<u>Given</u>,

Area of the triangle = 1/4 square meters

From the diagram,

Height = 2/5 m

<u>To find</u> : Length of the base

<u>Formula</u> : -

A = bh/2

Here,

A denotes Area

b denotes Base

h denotes Height

A = 1/4

h = 2/5

A = bh/2

Cross multiply,

A * 2 = bh

2A = bh

2 * (1/4) = b * (2/5)

(1 * 2)/4 = (b * 2)/5

2/4 = 2b/5

1/2 = 2b/5

Cross multiply,

1 * 5 = 2 * 2b

5 = 4b

b = 4/5 meters

Hence,

The length of the base is 4/5 meters.

5 0
2 years ago
A, B, C and D are four towns.
djverab [1.8K]

Three of the four towns are on the vertices of the triangle ΔCBD, through

which the bearing can calculated.

<h3>Response:</h3>
  • The bearing of D from B is approximately <u>209.05°</u>

<h3>Method by which the bearing is found;</h3>

From the given information, we have;

AC = AB = 25 km

∠BAC = 90° (definition of angle between north and east)

ΔABC = An isosceles right triangle (definition)

∠ACD = ∠ABC = 45° (base angles of an isosceles right triangle)

tan(\angle ABD) = \dfrac{45}{25}

  • \angle ABD = arctan \left(\dfrac{45}{25} \right)  \approx 60.945^{\circ}

The bearing of <em>D</em> from <em>B</em> is the angle measured from the north of <em>B</em> to the

direction of <em>D.</em>

<em />

Therefore;

  • The bearing of D from B ≈ 90° + (180° - 60.945°) = <u>209.05°</u>

Learn more about bearings in mathematics here:

brainly.com/question/10710413

5 0
2 years ago
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alekssr [168]

Answer:

dy/dx = (cos y + y sin x) / (cos x + x sin y)

Step-by-step explanation:

y cos x = x cos y

y (-sin x) + dy/dx cos x = x (-sin y dy/dx) + cos y

-y sin x + dy/dx cos x = -x sin y dy/dx + cos y

dy/dx (cos x + x sin y) = cos y + y sin x

dy/dx = (cos y + y sin x) / (cos x + x sin y)

5 0
3 years ago
65 - 2x ≥ 150, whats the answer!!!
Sidana [21]

Answer:

x <= -42.5

Step-by-step explanation:

65 - 2x >= 150

-2x >= 150 - 65

-2x >= 85

2x <= -85

x <= -85/2

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6 0
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Gala2k [10]

Answer:

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Step-by-step explanation:

because i said so, you should mark me brainliest

7 0
3 years ago
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