Papsdamatrix here is this picture

Mathematics

1 answer:

olganol [36]4 years ago

7 0

The answer is halogen
excuse the other person saying u need a bigger brain, u don’t

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Ms. Johnson buys a family-size bag of chips. She gives 20% to Jackie. Another 20% to Ronald. Ms. Johnson gives 1/4 to Mark and S

Kobotan [32]

Answer: 17.5%

Step-by-step explanation:

Percentage of chips given to Jackie = 20%

Percentage of chips given to Ronald = 20%

Percentage of chips given to Mark = 1/4 × 100 = 25%

From the above calculation, we can see that Ms Johnson has given out ((20% + 20% + 25%) = 65% worth of chips out. The percentage she'll have left will be:

= 100 - 65

= 35%

Since Susan takes half of what's left, the percent that Ms. Johnson has left to eat will be:

= 1/2 × 35%

= 17.5%

She has 17.5% left to eat.

3 0

3 years ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$