Sum of two angles that are complementary = 90°
<em>m</em>∠1 + <em>m</em>∠2 = 90°
Given :
<em>m</em>∠1 = 12°
Then :-
<h2>∴ <em>m</em>∠2 = 78°</h2>
4x^2 + x + 3 = 0
x = [-1 +/- sqrt (1^2 - 4 * 4 * 3)] / 8 = - 1 +/- sqrt ( --47) / 8
= ( - 1 +/- sqrt47i) / 8 = -0.125 + 0.857i , -0.125 - 0.857i
Correspondind sides, similar triangles
Answer:
A)
Step-by-step explanation:
To find the answer we must solve each of the systems separately. Starting with the first one:
x + y = 2
2x - y = 10
We must find what x or y is equal to and then replace it in the second equation. I'll go with y as it seems easier:
x + y = 2
y = 2 - x
Now that we found y we replace it in the second equation this way. Be careful with the signs, the minus with change our signs:
2x - (2 - x) = 10
2x - 2 + x = 10
3x = 12
x = 12/3
x = 4
Now that we have x, we replace the variable with its value in one of the equations. Again, for simplicity I'll go with the one that seems easier.
4 + y = 2
y = 2 - 4
y = - 2
We know that
When we have
Here ,
a is the leading coefficient
c is the constant term
so, we can compare it with
so, we get
so,
leading coefficient is 5
constant term is 6......................Answer
