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dexar [7]
3 years ago
15

1. Simplify the expression. Show your work .and steps 22 + (3^2 – 4^2)

Mathematics
1 answer:
erastova [34]3 years ago
6 0
PEMDAS...parentheses, then exponents, then multiplication/division, finally addition/subtraction...

22+(3^2-4^2)  inside the parentheses are exponents, so they are calculated first.

22+(9-16)  now you complete the operations inside the parentheses

22+(-7)  finally you do your addition/subtraction

22-7

15
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charlie paid $660 for 6 shirts and 4 belts. one shirt costs three times as much as one belt. if charlie bought 5 such shirts and
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4 0
3 years ago
PLEASE HELP, I'LL MARK BRAINLIEST.. Of the 37 teachers at Francesca's high school, 9 are female. What is the ratio of the number
lina2011 [118]

Answer:

In a school ratio of the number between male and female teachers is 5 : 9, If the number of female teachers is 81, what the number of male teachers.?

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1 Answer



Souvik Saha

, Business Analyst at BRIDGEi2i Analytics Solutions (2020-present)

Answered March 23, 2021

Let the total number of teachers be x

Given:

The ratio of the number between male and female teachers is 5:9

Then the number of female teachers is 81

So 9/14*x=81

or, x=81/9*14

or, x=9*14

Therefore x=126

So the total number of teachers is 126.

Hence the number of male teachers =

5/14*126

=5*9

=45

Hence, the number of male teachers is 45.

3 0
3 years ago
Read 2 more answers
Two chess players, A and B, are going to play 7 games. Each game has three possibleoutcomes: a win for A (which is a loss for B)
Lina20 [59]

Answer:

A) the possible outcomes for individual game is 210 games.

B) The possible outcome for this is 357 games.

C) Then the Possible Games are 267 games.

Step-by-step explanation:

A) Total number of individual games are 7 in which A ends up with 3 wins which give 4 remaining games. then there are two draw games from them. and in the end the remaining games are losses so,we useformula for combination:

                       (7C3)*(4C2)=210 \ games

B) Now Player A has 4 point that gives us 5 possibilities until we reach 7 games. Similarly B have 3 points which is same as player A gives us 5 possibilities until we reach 7 games. thus those two cases for player A and Player B can be stated as:

           (7C3)+(7C3)*(4C2)+(7C1)*(6C6)+(7C2)*(5C4)=357\  games

C) Lets say that player A ahs 4 points and player B has 3 points and all seven games have been played so.

c1) If player A has 4 wins and 3 losses then last win have to be in 7th match thus:the answer is (6C3).

c2) If player A has 3 win, 2 draws and 3 losses thus it means that final match cannot be a loss thus the answer is (6C2)*(5C3).

c3) Now lastly if player A has 1 win and 5 draws we can arrange them arbitrarily thus the answer here is (7C1).

c4) now If player A has 2 wins, 4 draws and 2 losses thus answer is (6C1)*(6C2)

Sum of all the cases is

               (6C3)+(6C2)*(5C3)+(7C1)+(6C1)*(6C2)=267\ games

4 0
3 years ago
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