Answer:
66.48% of full-term babies are between 19 and 21 inches long at birth
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean length of 20.5 inches and a standard deviation of 0.90 inches.
This means that 
What percentage of full-term babies are between 19 and 21 inches long at birth?
The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then
X = 21



has a p-value of 0.7123
X = 19



has a p-value of 0.0475
0.7123 - 0.0475 = 0.6648
0.6648*100% = 66.48%
66.48% of full-term babies are between 19 and 21 inches long at birth
Answer: sec (75) or csc (15)
Step-by-step explanation:
255 is in the 3rd quadrant where the secant is. Here, the tangent and cotangent is positive.
Reference angle for 255 is,
255 - 180 = 75 degrees.
Therefore, sec (255) = sec (75)
= csc (90 - 75) = csc (15)
I think the best option is 24.
Answer:
I think its C i think might be wrong
Write it in y= mx+b form. Subtract 5x from both sides to get 4y = -5x + 100. Divide by 4 so the answer would be y= -5/4x + 25.